将显示我的数据的表格
<table class="table" align="center">
<tr>
<td>Job Code</td>
<td><b><?php echo ' ' . $dataProvider->models[0]->job_code; ?></b></td>
</tr>
<tr>
<td>Client Code</td>
<td><b><?php echo ' ' . $dataProvider->models[0]->client_code; ?></b></td>
</tr>
<tr>
<td>Status</td>
<td ><b><span name="current" data-value="CDP"><?php echo ' ' . $dataProvider->models[0]->status; ?></b></td>
</tr>
</table>
JS -
$(document).ready(function() {
var i = 1;
$('.progress .circle').removeClass().addClass('circle');
$('.progress .bar').removeClass().addClass('bar');
setInterval(function() {
$('.progress .circle:nth-of-type(' + i + ')').addClass('active');
$('.progress .circle:nth-of-type(' + (i - 1) + ')').removeClass('active').addClass('done');
$('.progress .circle:nth-of-type(' + (i - 1) + ') .label').html('✓');
$('.progress .bar:nth-of-type(' + (i - 1) + ')').addClass('active');
$('.progress .bar:nth-of-type(' + (i - 2) + ')').removeClass('active').addClass('done');
i++;
if (i == 0) {
$('.progress .bar').removeClass().addClass('bar');
$('.progress div.circle').removeClass().addClass('circle');
i = 1;
}
}, 1000);
});
我给表字段一个名字,我想像 -
那样推进这个栏if(status=approved)
{
progress up to one step
}
elseif(status==digital)
{
progress up to Digital
}
elseif(status==CDP)
{
progress up to CDP
}
elseif(status==Printing)
{
progress up to Printing
}
and so on...
脚本应该从表字段获取值,并且进度和步骤栏可以达到适当的状态。怎么做到这一点?
CodePen Link- http://codepen.io/anon/pen/RPBmXZ