Question

（忽略g.text和p.content返回＆＃34;您无权查看此内容＆＃34;来自plug.dj）我收到错误

Traceback (most recent call last):
  File "plugling.py", line 20, in <module>
    r.send('{"a":"auth","p":"'+g+'","t":'+t+'}')
TypeError: cannot concatenate 'str' and 'Response' objects

运行此代码时：

import time
from websocket import create_connection
import requests
import calendar

slug = 'sfoc'
r = create_connection("wss://godj.plug.dj/socket")
t = calendar.timegm(time.gmtime())

token = 'https://plug.dj/_/auth/token'
join = 'https://plug.dj/_/rooms/join'
pl = {'slug': 'sfoc'}

g = requests.get(token)
print g.text

p = requests.post(join, data=pl)
print p.content

r.send('{"a":"auth","p":"'+g+'","t":'+t+'}')
result = r.recv()
print result
r.close()

我也不喜欢使用％s作为变量。我不知道自己做错了什么。提前致谢，如果我没有清楚地解释清楚，请告诉我。

Answer 1

您正在尝试连接Response对象：

g = requests.get(token)
# ...
r.send('{"a":"auth","p":"'+g+'","t":'+t+'}')

g是响应对象。您想获得文本值：

r.send('{"a": "auth", "p": "' + g.text + '", "t":' + t + '}')

如果您尝试在那里发送JSON数据，可能需要查看json module：

r.send(json.dumps({'a': 'auth', 'p': g.text, 't': t}))

TypeError：无法连接＆＃39; str＆＃39;和“回应”＃39;对象

1 个答案: