Question

我一直在关于类似问题的Stack Overflow上看一些其他问题。据说这个问题是由函数递归引起的，但我不能100％确定这是否是相同的情况 - 正如您将在下面看到的那样。

这是罪魁祸首函数，抛出错误：

/* inits AND parses research projects from database */
Game.prototype.initAndParseResearch = function(city, research){
    var research = JSON.parse(research);
    var d = new Date().getTime();

    //object that contains active research projects
    var projects = research.active;

    //loop through each active project and "init" the research
    for(var project in projects){
        var obj = this.GameCfg.research_projects[project];
        var timeUntil = (projects[project].started + (obj.time * 60 * 1000)) - d;

        //minimum 0 - don't want a negative time for setTimeout()
        if(timeUntil < 0){
            timeUntil = 0;
        }

        //start timeout
        var timeout = setTimeout(function(){
            console.log('YOU FAILED.');
            //this.researchFinished(city, project);
        }.bind(this), 5000);


        city.research = research;
        city.research.active[project] = {
            timeout : timeout
        };
    }
}

针对细节抛出的错误：

C:\xampp\htdocs\node_modules\mysql\lib\protocol\Parser.js:82
        throw err;
              ^
RangeError: Maximum call stack size exceeded

C:\xampp\htdocs>

现在，罪魁祸首似乎是当函数试图存储从setTimeout返回的句柄时。为什么我不能存储超时参考？我可以不存储它并使一切顺利运行，但如果我需要运行clearTimeout，我就不会引用超时对象。

更新代码

/* inits AND parses research projects from database */
Game.prototype.initAndParseResearch = function(Player, city, research){
    var research = JSON.parse(research);
    var d = new Date().getTime();

    //object that contains active research projects
    var projects = research.active;

    //loop through each active project and "init" the research
    for(var project in projects){
        var obj = this.GameCfg.research_projects[project];
        var timeUntil = (projects[project].started + (obj.time * 60 * 1000)) - d;

        //minimum 0 - don't want a negative time for setTimeout()
        if(timeUntil < 0){
            timeUntil = 0;
        }

        city.research = research;

        //start timeout
        var timeout = setTimeout(function(){
            this.researchFinished(Player, city, project);
        }.bind(this), timeUntil);

        Player.timeouts['research_'+project] = timeout;
    }
}

节点范围错误，超出最大调用堆栈大小

0 个答案: