我有一个脚本,我一直在与之争斗一周。
我有一个带有id(“content”)div的页面。现在我将一些内容,一个包含在div标签中的表单特定加载到这个div VIA Ajax中,它显示正常
现在,挑战是 - 当提交表单时,我正在调用一个函数来禁用该div标签中元素的所有字段。我总是得到错误“未定义”。
似乎我带入页面的div无法被javascript识别..
我搜索过google,bing,yahoo ..我还没找到解决方案......
拜托,我该怎么办?
我已经包含了以下代码 -
+++++++++ 我的外部javascript文件的下面代码
++++++++++++++++++++
// JavaScript Document
var doc = document;
var tDiv;
var xmlHttp;
var pgTitle;
function getXMLObj(){
if (window.XMLHttpRequest){
// code for IE7+, Firefox, Chrome, Opera, Safari
Obj = new XMLHttpRequest();
}
else if (window.ActiveXObject){
// code for IE6, IE5
Obj = new ActiveXObject("Microsoft.XMLHTTP");
}
else{
alert("Your browser does not support Ajax!");
}
return Obj;
}
function loadCont(toLoad, view){
doc.getElementById('loadBlank').innerHTML = '<div id="loading">Processing Request...</div>';
var url;
switch(toLoad){
case 'CI':
pgTitle = "Administration - Company Information";
url = "comp_info.php?v=" + view + "&sid=" + Math.random();
break;
case 'JB':
pgTitle = "Administration - Jobs";
url = "jobs.php?v=" + view + "&sid=" + Math.random();
break;
case 'US':
pgTitle = "Administration - Users";
url = "users.php?v=" + view + "&sid=" + Math.random();
break;
case 'EP':
pgTitle = "Administration - Employees";
url = "emp.php?v=" + view + "&sid=" + Math.random();
break;
case 'AP':
pgTitle = "Administration - Recruitments";
url = "applicants.php?v=" + view + "&sid=" + Math.random();
break;
case 'JV':
pgTitle = "Administration - Recruitments";
url = "jobvacancy.php?v=" + view + "&sid=" + Math.random();
break;
}
xmlHttp = getXMLObj();
if (xmlHttp !== null && xmlHttp !== undefined){
xmlHttp.onreadystatechange = loadingContent;
xmlHttp.open('GET', url, true);
xmlHttp.send(null);
}
}
function loadingContent(){
if (xmlHttp.readyState == 4 || xmlHttp.readyState == 'complete'){
//Show the loading and the title, but hide the content...
if (xmlHttp.status == 200){
doc.getElementById('dMainContent').innerHTML = parseScript(xmlHttp.responseText);
doc.getElementById('loadBlank').innerHTML = '';
}
else{
doc.getElementById('dMainContent').innerHTML = 'Sorry..Page not available at this time. <br />Please try again later';
doc.getElementById('loadBlank').innerHTML = '';
}
}
if (xmlHttp.readyState < 4){
//Show the loading and the title, but hide the content...
doc.getElementById('ActTitle').innerHTML = pgTitle;
doc.getElementById('dMainContent').innerHTML = '';
}
}
function valCompInfo(){
//First Disable All the elements..
alert('I was hree');
DisEnaAll('CompForm');
//Now..lets validate the entries..
}
function DisEnaAll(contId){
//alert(doc.getElementById(contId).elements);
var theId = doc.getElementById(contId).elements;
try{
var numElems = theId.length;
for (var i=0; i < (numElems - 1); i++){
(theId[i].disabled == false) ? (theId[i].disabled = true) : (theId[i].disabled = false);
}
}
catch(e){
var msg = "The following error occurred: \n\n";
msg += e.description
alert(msg);
}
}
// http://www.webdeveloper.com/forum/showthread.php?t=138830
function parseScript(_source) {
var source = _source;
var scripts = new Array();
// Strip out tags
while(source.indexOf("<script") > -1 || source.indexOf("</script") > -1) {
var s = source.indexOf("<script");
var s_e = source.indexOf(">", s);
var e = source.indexOf("</script", s);
var e_e = source.indexOf(">", e);
// Add to scripts array
scripts.push(source.substring(s_e+1, e));
// Strip from source
source = source.substring(0, s) + source.substring(e_e+1);
}
// Loop through every script collected and eval it
for(var i=0; i<scripts.length; i++) {
try {
eval(scripts[i]);
}
catch(ex) {
// do what you want here when a script fails
}
}
// Return the cleaned source
return source;
}
此代码位于javascript为
的主页面上<div id="dMainContent">
</div>
</body>
</html>
最后,我通过ajax加载的页面内容..
<div style="width:738px" id="CompForm">
<div class="tdright">
<a href="#" class="lnkBtn" onclick="valCompInfo();"><?php echo $btnNm; ?></a>
</div>
</div>
那是代码..
谢谢
答案 0 :(得分:2)
问题在于div标签(id“CompForm”),它不是HTML表单。
“elements”是表单元素的集合,而不是div元素。因此,在尝试访问div.elements时,属性是未定义的。
参见MSDN,form.elements是DOM级别1的一部分(根据MSDN)
http://msdn.microsoft.com/en-us/library/ms537449%28v=VS.85%29.aspx
答案 1 :(得分:0)
将您的Javascript函数或外部JS文件添加到原始页面。
答案 2 :(得分:0)
这不是JavaScript ......
doc.getElementById(contId).elements
但是在你的JavaScript中使用...你绝对不会得到任何东西。 (空)
我认为这也不合适:
theId[i].disabled == false
答案 3 :(得分:-1)
编辑:请注意每条评论:这不是答案:)请参阅评论以了解原因。
作为建议的学习辅助工具,仅作为答案。
不应该
xmlHttp.onreadystatechange = loadingContent;
是
xmlHttp.onreadystatechange = loadingContent();
或
loadingContent();
如果你想像那样分配它,那个函数应该返回一个值...