我有两张表
ItemTable_One
id itemID Date qty
===================================================
1 1 2015-07-1 10
2 1 2015-07-3 20
3 2 2015-07-5 30
4 2 2015-07-7 40
ItemTable_Two
id itemID Date qty
===================================================
1 1 2015-07-2 50
2 1 2015-07-4 60
3 3 2015-07-6 70
4 3 2015-07-8 80
我想检索日期范围内 itemID等于1 的数据 例如（2015-07-1和2015-07-30之间的日期范围）
itemID Date ItemTableOne_qty ItemTableTwo_qty
============================================================================
1 2015-07-1 10 0
1 2015-07-3 20 0
1 2015-07-2 0 50
1 2015-07-4 0 60
我已尝试union加入和subquery来做这件事，但我在SQL查询中非常弱。
答案 0 :(得分：2)
您可以使用UNION ALL获取所需的所有数据：
SELECT ItemTable_One.itemID, ItemTable_One.Date, ItemTable_One.qty as ItemTableOne_qty, 0 as ItemTableTwo_qty
FROM ItemTable_One
WHERE ItemTable_One.itemID = 1 AND
ItemTable_One.Date BETWEEN '2015-07-01' AND '2015-08-01'
UNION ALL
SELECT ItemTable_Two.itemID, ItemTable_Two.Date, 0 as ItemTableOne_qty, ItemTable_Two.qty as ItemTableTwo_qty
FROM ItemTable_One
WHERE ItemTable_Two.itemID = 1 AND
ItemTable_Two.Date BETWEEN '2015-07-01' AND '2015-08-01'
答案 1 :(得分：1)
试试这个：
select itemID, Date, qty as ItemTableOne_qty, 0 as ItemTableTwo_qty
from ItemTable_One
where ItemID = 1
and date >= '20150701'
and date < '20150731'
union all
select itemID, Date, 0 as ItemTableOne_qty, qty as ItemTableTwo_qty
from ItemTable_Two
where ItemID = 1
and date >= '20150701'
and date < '20150731'
日期的上限是故意＆lt;比想要的日期+1所以，如果它是一个有时间的日期时间，那么最后一天也将被包括在内。
答案 2 :(得分：1)
您可以使用FULL OUTER JOIN：
SELECT COALESCE(t1.itemID, t2.itemID) AS itemID,
COALESCE(t1.[Date], t2.[Date]) AS [Date],
COALESCE(t1.qty, 0) AS ItemTableOne_qty,
COALESCE(t2.qty, 0) AS ItemTableTwo_qty
FROM ItemTable_One AS t1
FULL OUTER JOIN ItemTable_Two AS t2 ON t1.itemID = t2.itemID AND t1.[Date] = t2.[Date]
WHERE COALESCE(t1.itemID, t2.itemID) = 1 AND
COALESCE(t1.[Date], t2.[Date]) BETWEEN '2015-07-01' AND '2015-07-31'
ORDER BY COALESCE(t1.[Date], t2.[Date])
这会将源表中具有相同[Date]值的记录放入输出表的同一行。
如果ItemTable_One 始终的记录与[Date]的记录具有单独的ItemTable_Two值，则其他答案中提出的UNION解决方案更可行
答案 3 :(得分：0)
您使用FULL JOIN或UNION ALL执行此操作（具体取决于所需的输出）
只要两个表之间没有相同的日期，FULL JOIN就可以获得您显示的结果。如果两个表中都存在这样的日期，那么每个日期都会得到一行，并且两个值都已填充。
要使用的查询是：
SELECT COALESCE(t1.itemID, t2.itemID) itemID, COALESCE(t1.Date, t2.Date) Date,
ISNULL(t1.qty, 0) ItemTableOne_qty, ISNULL(t2.qty, 0) ItemTableTwo_qty
FROM ItemTable_One t1 FULL JOIN ItemTable_Two t2
ON t1.itemID = t2.itemID AND t1.Date = t2.Date
WHERE COALESCE(t1.itemID, t2.itemID) = 1 AND
COALESCE(t1.Date, t2.Date) BETWEEN '2015-07-01' AND '2015-08-01'
UNION ALL将允许您获得您展示的结果，并将创建两个表中存在相同日期的重复行。任何行中始终至少有1'0'值。
要使用的查询是：
SELECT itemID, Date, qty ItemTableOne_qty, 0 ItemTableTwo_qty
FROM ItemTable_One
WHERE itemID = 1 AND Date BETWEEN '2015-07-01' AND '2015-08-01'
UNION ALL
SELECT itemID, Date, 0 ItemTableOne_qty, qty ItemTableTwo_qty
FROM ItemTable_Two
WHERE itemID = 1 AND Date BETWEEN '2015-07-01' AND '2015-08-01'
答案 4 :(得分：0)
这将是我们基于您的样本数据获得相同结果的另一种方式
declare @ItemTable_One table (id int, itemID int, Date date, qty int)
insert into @ItemTable_One values
(1, 1, '2015-07-1', 10),
(2, 1, '2015-07-3', 20),
(3, 2, '2015-07-5', 30),
(4, 2, '2015-07-7', 40)
declare @ItemTable_Two table (id int, itemID int, Date date, qty int)
insert into @ItemTable_Two values
(1, 1, '2015-07-2', 50),
(2, 1, '2015-07-4', 60) ,
(3, 3, '2015-07-6', 70) ,
(4, 3, '2015-07-8', 80)
;with CTE AS (
select i.itemID As ItemID1,ii.itemID As ItemID2,i.Date As Dated1,ii.Date As Dated2,i.qty as qty,ii.qty As qty1 from @ItemTable_One i
CROSS APPLY (select * from @ItemTable_Two )ii
where i.id = ii.id AND i.itemID = ii.itemID
)
select * from (
Select ItemID1 As item,Dated1 AS Date, qty,'' as qty1 from CTE
UNION
Select ItemID2 As item,Dated2 AS Date,'' as qty,qty1 from CTE)T
--ORDER BY t.qty desc ,t.qty1
答案 5 :(得分：0)
使用内联视图来简化先前答案中使用的horrid sql：
mode