Question

我正在尝试找到一种方法来搜索向量以查找用户输入的字符串。不知道如何开始。一旦找到字符串，我必须删除它的索引并打印索引中的其余字符串。

void addNames(vector<string>& names)
{
 names.push_back("Seppi");
 names.push_back("Farrell");
 names.push_back("Burton");
}

void print(vector<string> names)
{
 for (int i = 0; i < names.size(); i++)
     {
      cout << names[i] << endl;
     }
}

int findName(vector<string> names, string nameToErase)
{
    int return_value = -1;
    names.find()

    return return_value;
}

int main()
{
 vector<string> names;

 addNames(names);

 string nameToErase;
 cin >> nameToErase;

 int indexFound = findName(names, nameToErase);

}

Answer 1

有std :: find方法。实施例

#include <iostream>
#include <vector>
#include <algorithm>
#include <string>

using namespace std;

int main(int argc, char *argv[])
{
    vector< string > v;
    v.push_back( "AAAA" );
    v.push_back( "BBBB" );
    v.push_back( "BBBB1" );
    v.push_back( "BBBB33" );
    vector< string >::iterator i = find( v.begin(), v.end(), "BBBB1" );
    if( i != v.end() )
    {
        cout << "Found " << *i << " on index " << i - v.begin() << endl;
    }
    else
    {
        cout << "Not found" << endl;
    }
    return 0;
}

http://en.cppreference.com/w/cpp/algorithm/find

Answer 2

此方法可以使用

void findAndErase(vector<string> & names, string nameToErase) {
    vector<string>::iterator pos = std::find(names.begin(), names.end(), nameToErase);
    if (pos != names.end())
        names.erase(pos);
}

在向量中搜索字符串

2 个答案: