如何在循环工作时使这个javascript异步?

时间:2015-07-18 21:44:45

标签: javascript google-dfp

我试图让google gpt标签刷新最多次数,如果加载时它会变回空白。

<script type="text/javascript">
    googletag.cmd.push(function() {
    var slot1 = googletag.defineSlot("/gtpConfigStuff",[300,600],"gtpConfigStuff")
    .addService(googletag.pubads())
    .setTargeting("pos", "BTF")
    .setTargeting("URL", encodeURIComponent(window.location));
    googletag.enableServices();
    googletag.display("gtpConfigStuff");
    googletag.pubads().addEventListener('slotRenderEnded', function(event) {
    var tries = 0;
    while (tries<=2 && event.isEmpty==true) {
    //googletag.pubads().refresh([slot1]);
    //setTimeout(function() {
      tries++;
      console.log(tries);
      //}, 1000);
      }
      console.log("done");
     });
  });
 </script>

通过上面的注释,它可以正常工作。 使用刷新函数调用它将无限循环。 我认为setTimeout可能允许刷新完成。

感谢。

1 个答案:

答案 0 :(得分:0)

您的脚本将无限期加载,因为您无限期地重置tries变量

var tries = 0; // Set your variable here...
googletag.pubads().addEventListener('slotRenderEnded', function(event) {
  // ...and not here. Otherwise it will always reset to 0 when the event triggers.
  // "tries" will still be available in here though as a closure so you can still use it
  if (tries<=2 && event.isEmpty==true) {
    googletag.pubads().refresh([slot1]);
    tries++;
  }
});