Question

我试图显示我的数据库中已被MySql查询提取的信息。我设置了这个错误

Parse error: syntax error, unexpected '<' in C:\xampp\htdocs\1\search.php on line 14

以下是search.php的代码

    <?php
if (isset($_POST['searchterm'])){
mysql_connect("localhost","root","Oliver");
mysql_select_db("videos");

$search = mysql_real_escape_string(trim($_POST['searchterm']));

$find_videos = mysql_query("SELECT * FROM `videos` WHERE `keywords` LIKE'%$search%'");
while($row = mysql_fetch_assoc($find_videos))
{
    $name = $row['name'];

    echo "<table">";
  echo "<tr>";
    echo "<td>$name</td>";
  echo "</tr>";
  echo "<tr>";
  echo  "<td>$name</td>";
  echo "</tr>";
echo "</table>";
}
}
?>
<?php
include('session.php');
?>
<!DOCTYPE html>
<html>
  <head>
  <link href="http://vjs.zencdn.net/4.12/video-js.css" rel="stylesheet">
  <link rel="icon" type="image/ico" href="images/favicon.ico">
<script src="http://vjs.zencdn.net/4.12/video.js"></script>
<link href="http://vjs.zencdn.net/4.12/video-js.css" rel="stylesheet">
<script src="http://vjs.zencdn.net/4.12/video.js"></script>
<style type="text/css">
  .vjs-default-skin .vjs-control-bar { font-size: 125% }
</style>
    <meta charset="utf-8">
    <title>Network TV | search</title>
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <link rel="stylesheet" href="css/bootstrap.css" />
    <link href="css/font-awesome.css" rel="stylesheet" />
    <link href="css/3.1.1/animate.css" rel="stylesheet" />
    <link rel="stylesheet" href="css/styles.css" />
  </head>
  <body style="overflow-x: hidden">
    <nav class="navbar navbar-default navbar-fixed-top">
      <div class="container">
        <div class="navbar-header">
          <button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar">
            <span class="sr-only">Toggle navigation</span>
            <span class="icon-bar"></span>
            <span class="icon-bar"></span>
            <span class="icon-bar"></span>
          </button>
          <a class="navbar-brand" href="#">Network TV</a>
        </div>
        <div id="navbar" class="navbar-collapse collapse">
          <ul class="nav navbar-nav">
            <li class=""><a href="\1\index.php">Home</a></li>
          </ul>
        </div><!--/.nav-collapse -->
      </div>
    </nav>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
    <script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.4/js/bootstrap.min.js"></script>

    <script src="js/scripts.js"></script>
</html>

我已经有表单设置将信息发布到此页面。显示信息时，它只是悬挂在屏幕左上方的列表中，我试图将其显示在屏幕左侧的一个表格中。以下是我尝试过的一些例子。

echo "<table style=text-align:center">"";
  echo "<tr>";
    echo "<td>$name</td>";
  echo "</tr>";
  echo "<tr>";
  echo  "<td>$name</td>";
  echo "</tr>";
echo "</table>";

这给了我错误Parse error: syntax error, unexpected '"<table style="' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';' in C:\xampp\htdocs\1\search.php on line 13

然后我试过了。

        echo "<table style=""width:100%">";
  echo "<tr>";
    echo "<td>Jill</td>";
  echo "</tr>";
  echo "<tr>";
  echo  "<td>Eve</td>";
  echo "</tr>";
echo "</table>";

我收到错误Parse error: syntax error, unexpected '"width:100%"' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';' in C:\xampp\htdocs\1\search.php on line 14

我不知道什么是错的。任何帮助都非常感谢

标记为重复 我不知道我在修什么，所以不幸的是它对我毫无帮助。我相信它会帮助其他人以后下线。

图片和更新 这是一个现在看起来如何的图像。 enter image description here

正如您所看到的，每次都会重复“电影名称”。

代码更新

echo '<table style="width:100%">';
  echo "<tr>";
    echo "<td>Name of movie</td>";
  echo "</tr>";
  echo "<tr>";
  echo  "<td>$name</td>";
  echo "</tr>";
echo "</table>";

更新2

<?php
if (isset($_POST['searchterm'])){
mysql_connect("localhost","root","Oliver");
mysql_select_db("videos");

$search = mysql_real_escape_string(trim($_POST['searchterm']));

$find_videos = mysql_query("SELECT * FROM `videos` WHERE `keywords` LIKE'%$search%'");
while ($row = mysql_fetch_array($find_videos, MYSQL_BOTH)) {
{

    $name = $row['name'];
}
}
}
?>
<?php
include('session.php');
?>
<!DOCTYPE html>
<html>
  <head>
  <link href="http://vjs.zencdn.net/4.12/video-js.css" rel="stylesheet">
  <link rel="icon" type="image/ico" href="images/favicon.ico">
<script src="http://vjs.zencdn.net/4.12/video.js"></script>
<link href="http://vjs.zencdn.net/4.12/video-js.css" rel="stylesheet">
<script src="http://vjs.zencdn.net/4.12/video.js"></script>
<style type="text/css">
  .vjs-default-skin .vjs-control-bar { font-size: 125% }
</style>
    <meta charset="utf-8">
    <title>Network TV | search</title>
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <link rel="stylesheet" href="css/bootstrap.css" />
    <link href="css/font-awesome.css" rel="stylesheet" />
    <link href="css/3.1.1/animate.css" rel="stylesheet" />
    <link rel="stylesheet" href="css/styles.css" />
  </head>
  <body style="overflow-x: hidden">
    <nav class="navbar navbar-default navbar-fixed-top">
      <div class="container">
        <div class="navbar-header">
          <button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar">
            <span class="sr-only">Toggle navigation</span>
            <span class="icon-bar"></span>
            <span class="icon-bar"></span>
            <span class="icon-bar"></span>
          </button>
          <a class="navbar-brand" href="#">Network TV</a>
        </div>
        <div id="navbar" class="navbar-collapse collapse">
          <ul class="nav navbar-nav">
            <li class=""><a href="\1\index.php">Home</a></li>
          </ul>
        </div><!--/.nav-collapse -->
      </div>
    </nav>
        <div class="v-center">
                <h1 class="text-center" style="color:white">Welcome to Network TV</h1>
                <table class="table" style="width:10%">
                        <thead>
                            <tr>
                                <th>Movie name</th>
                            </tr>
                        </thead>
                        <tbody>
                            <tr>
                                <td><?php echo $name; ?></td>
                            </tr>
                        </tbody>
                    </table>
        </div>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
    <script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.4/js/bootstrap.min.js"></script>

    <script src="js/scripts.js"></script>
</html>

语法错误，意外'＆lt;'在尝试将查询结果显示到表中时。 PHP

0 个答案: