我在两个进程之间有一个共享内存块(1024字节),我有一个地址指向。我想将一些数据复制到这个共享内存,并在另一个进程上读取它。来自C背景,将记录映射到此地址,然后写入记录似乎最简单,但它似乎没有正确复制。
目前,我正在尝试使用未经检查的转换将指针转换为指向记录的类型,并将其复制到记录中,但是当我将原始有效负载与接收到的有效负载进行比较时,我发现数据存在差异。第二个过程。
这是正确的做法吗?:
type Payload_Array_Type is array (1..255) of Integer_32;
type Common_Buffer_Type is
record
Size : Integer_32;
Payload : Payload_Array_Type;
end record;
type Common_Buffer_Ptr_Type is access Common_Buffer_Type;
function Convert_Common_Memory_Ptr is new Unchecked_Conversion (
Source => System.Address,
Target => Common_Buffer_Ptr_Type);
Common_Memory_Ptr : System.Address;
procedure Copy_To_Common_Buffer
(
Size : Integer_32;
Payload : Payload_Array_Type
) is
Common_Buffer_Ptr : Common_Buffer_Ptr_Type;
begin
Common_Buffer_Ptr := Convert_Common_Memory_Ptr(Common_Memory_Ptr);
Common_Buffer_Ptr.Size := Size;
Common_Buffer_Ptr.Payload(1..255) := Payload(1..255);
end Copy_To_Common_Buffer;
答案 0 :(得分:2)
我会尝试这样做:
procedure Payload is
type Payload_Array_Type is array (1..255) of Integer_32;
type Common_Buffer_Type is record
Size : Integer_32;
Payload : Payload_Array_Type;
end record;
for Common_Buffer_Type use record -- representation clause should be common to both processes
Size at 0 range 0 .. 31;
Payload at 0 range 32 .. 1023;
end record;
for Common_Buffer_Type'Size use 1024; -- check this is also used in the other process.
type Common_Buffer_Ptr_Type is access Common_Buffer_Type;
Common_Memory_Ptr : System.Address; -- assuming this is where the shared object resides with a real address, possibly make it constant
procedure Copy_To_Common_Buffer (Size : in Integer_32;
Payload : in Payload_Array_Type) is
Common_Buffer : Common_Buffer_Type;
for Common_Buffer'Address use Common_Memory_Ptr; -- address overlay
begin
Common_Buffer := (Size => Size,
Payload => Payload);
end Copy_To_Common_Buffer;
begin
Copy_To_Common_Buffer (9,(others => 876));
end Payload;
类型定义应该对两个进程是通用的,并且请注意我使用了一个表示子句来指定组件的位置。
我使用地址覆盖来指定我写作的位置,并一次性写出整个记录。
另请查看@Brian Drummond建议使用pragma volatile。