如何将字典值与pandas数据帧值匹配？

Question

我有一本字典：

dictionary = {"A": [1, 2, 3, 4, 5, 6, 7, 8], 
"B": [1, 2, 3, 4,], "C": [1, 2, 3, 4, 5, 6, 7],
"D": [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 
"E": [1, 2, 3, 4, 5, 6]}

和一个pandas数据帧：

    name  value
0    one      1
1    two      2
2  three      3
3   four      4
4   five      5
5    six      6
6  seven      7
7  eight      8
8   nine      9
9    ten     10

我需要做的是＆＃34;匹配＆＃34;字典中每个键内的值，其值为＆＃34;值＆＃34; pandas数据帧的列，然后将字典中的值替换为与列名对应的值。

知道如何到达那里吗？

非常感谢

Answer 1

# your data
# ===================================
dictionary = {"A": [1, 2, 3, 4, 5, 6, 7, 8], 
"B": [1, 2, 3, 4,], "C": [1, 2, 3, 4, 5, 6, 7],
"D": [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 
"E": [1, 2, 3, 4, 5, 6]}

df

    name  value
0    one      1
1    two      2
2  three      3
3   four      4
4   five      5
5    six      6
6  seven      7
7  eight      8
8   nine      9
9    ten     10

# processing
# ===================================
df1 = df.set_index('value')

for key in dictionary.keys():
    dictionary[key] = df1.loc[dictionary[key]].values.ravel().tolist()

print(dictionary)


{'A': ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight'], 'B': ['one', 'two', 'three', 'four'], 'E': ['one', 'two', 'three', 'four', 'five', 'six'], 'D': ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten'], 'C': ['one', 'two', 'three', 'four', 'five', 'six', 'seven']}