Question

我有一个文件text.txt，其中包含ff：

apple boy 'cat'
dog, egg fin
goat hat ice!

我需要使用空格和特殊字符拆分文本文件，同时忽略新行，这样输出就像这样一个数组：

["apple", "boy", "'", "cat", "'", "dog", "egg", "fin", "goat", "hat", "ice", "!"]

但到目前为止，我的代码输出结果是这样的：它返回每个字符的字符串，甚至保留空格......

["a", "p", "p", "l", "e", "b", "o", "y", "'", "c", "a", "t", "'", "\n," "d", "o", "g", "e", "g", "g", "f", "i", "n", "\n", "g", "o", "a", "t", "h", "a", "t", "i", "c", "e", "!", "\n" ]

这是我的代码：

file=open(text.txt)

for i in file:
        i.split(" ")
        b+=i


print b

如果不允许导入任何模块该怎么办？特别是re模块？

Answer 1

使用临时字符串，找到非空字母数字字符将它们包装在两侧的空格中，然后在末尾分割

lines ="""apple boy 'cat'
dog, egg fin
goat hat ice!"""

out = []
for line in lines.splitlines():
    temp = ""
    for ch in line:
        if ch.isalnum():
            temp+= ch
        else:
            temp += " {} ".format(ch)
    out.extend(temp.split())
print(out)

输出：

['apple', 'boy', "'", 'cat', "'", 'dog', ',', 'egg', 'fin', 'goat', 'hat', 'ice', '!']

使用您的文件只需迭代文件对象并应用相同的逻辑：

with open("text.txt") as f:
    out = []
    for line in f:
        temp = ""
        for ch in line:
            if ch.isalnum():
                temp += ch
            else:
                temp += " {} ".format(ch)
        out.extend(temp.split())

您还可以使用一组标点符号并更改逻辑检查，如果字符集出现在集合中：

st = set("""!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~""")
with open("text.txt") as f:
    out = []
    for line in f:
        temp = ""
        for ch in line:
            if ch not in st:
                temp += ch
            else:
                temp += " {} ".format(ch)
        out.extend(temp.split())

Answer 2

将所有行放入单个字符列表（l）。

然后检查字符是否是字母数字，而当前字符是字母数字（isalnum()），它被组合成字符串（comb），此字符串被添加到输出list（out）当找到非字母数字时，然后单独添加非字母数字，直到再次找到字母数字。

然后从换行符和空格中过滤出

out。

with open('text.txt') as f:
    l = f.readlines()

    # separates each character into a list
    l = list(l)

    # output list
    out = []

    # string in which alphanumerics will be combined
    comb = ''

    # loops through chars
    # comb is added with chars while char is alphanumberic,
    # comb is added to out when a non-alphanumeric char is detected 
    # and then it resets, and the char detected as punc is added as well
    for ch in l:
        if ch.isalnum():
            comb += ch
        else:
            out.append(comb)
            out.append(ch)
            comb = ''

    # filters out from space and newlines
    out = [ s for s in out if s != '' and s != '\n' and s != ' ' ]

    print(out)

输出：

['apple', 'boy', "'", 'cat', "'", 'dog', ',', 'egg', 'fin', 'goat', 'hat', 'ice', '!']

在python中拆分多个分隔符的字符串

2 个答案: