Question

我正在尝试为我的网站实施一个基本联系表单，其中包含三个字段：姓名，电子邮件和消息。我正在使用的PHP代码如下：

<?php
// Fetching Values from URL.
$name = $_POST['name2'];
$email = $_POST['email2'];
$message = $_POST['message2'];

$email = filter_var($email, FILTER_SANITIZE_EMAIL); // Sanitizing E-mail.

// After sanitization Validation is performed
if (filter_var($email, FILTER_VALIDATE_EMAIL)) 
{
        $subject = $name;
        // To send HTML mail, the Content-type header must be set.
        $headers = 'MIME-Version: 1.0' . "\r\n";
        $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
        $headers .= 'From:' . $email. "\r\n"; // Sender's Email
        $headers .= 'Cc:' . $email. "\r\n"; // Carbon copy to Sender
        $template = '<div style="padding:50px; color:white;">Hello ' . $name . ',<br/>'
        . '<br/>Thank you for contacting me!<br/><br/>'
        . 'Name:' . $name . '<br/>'
        . 'Email:' . $email . '<br/>'
        . 'Message:' . $message . '<br/><br/>'
        . 'This is a Contact Confirmation mail.'
        . '<br/>'
        . 'I\'ll get back to you as soon as possible .</div>';
        $sendmessage = "<div style=\"background-color:#7E7E7E; color:white;\">" . $template . "</div>";
        // Message lines should not exceed 70 characters (PHP rule), so wrap it.
        $sendmessage = wordwrap($sendmessage, 70);
        // Send mail by PHP Mail Function.
        mail("myemailid@gmail.com", $subject, $sendmessage, $headers);
        echo "Your message has been sent successfully!";
} 
else 
{
    echo "<span>* invalid email *</span>";
}
?>

（显然我用实际的电子邮件地址替换了myemailid@gmail.com）

调用此php代码的JavaScript文件如下：

$(document).ready(function() {
$("#submit").click(function() {
var name = $("#name2").val();
var email = $("#email2").val();
var message = $("#message2").val();

// Checking for blank fields.
if (name == '' || email == '' || message == '') 
{
    alert("Please Fill Required Fields");
} 
else 
{
    $.post("contact_form.php", 
    {
        name2: name,
        email2: email,
        message2: message,
    }, function(data) {

    if (data == "Your message has been sent successfully!") {
    $("#footer-form")[0].reset(); // To reset form fields on success.
    }
    });
}
});
});

点击发送＆＃39;按钮没有任何反应我在这做错了什么？我知道这是基本的，但一些帮助将非常感激！

如果这有帮助：

<div class="col-sm-6">
                            <div class="footer-content">
                                <form role="form" id="footer-form">
                                    <div class="form-group has-feedback">
                                        <label class="sr-only" for="name2">Name</label>
                                        <input type="text" class="form-control" id="name2" placeholder="Name" name="name2" required>
                                        <i class="fa fa-user form-control-feedback"></i>
                                    </div>
                                    <div class="form-group has-feedback">
                                        <label class="sr-only" for="email2">Email address</label>
                                        <input type="email" class="form-control" id="email2" placeholder="Enter email" name="email2" required>
                                        <i class="fa fa-envelope form-control-feedback"></i>
                                    </div>
                                    <div class="form-group has-feedback">
                                        <label class="sr-only" for="message2">Message</label>
                                        <textarea class="form-control" rows="8" id="message2" placeholder="Message" name="message2" required></textarea>
                                        <i class="fa fa-pencil form-control-feedback"></i>
                                    </div>
                                    <input type="button" id="submit" value="Send" class="btn btn-default">
                                </form>
                            </div>
                        </div>

此外，我点击发送按钮后的php URL如下：

/index.html?name2=John+Doe&email2=johndoe%40example.com&message2=This+is+a+test+message.

自从我将按钮类型更改为＆＃39;按钮＆＃39;而不是“提交”，按钮不会重新加载页面或给我这个网址。

Answer 1

错误是语法错误，}之后的echo "Your message has been sent successfully!";。

修改

此外，请务必确认是否已调用$("#submit").click。

您还需要取消表单提交操作（您使用ajax发送邮件）。

Answer 2

要在PHP中阅读表格参数，您需要使用$ _GET。在该级别进行调试。看看你是否在服务器端获得这些值。另外，请确保您正在读取js中的所有值。提供HTML块会有所帮助。

联系表格没有回应

2 个答案: