我正在开发一个页面,我需要显示一些框(使用ng-repeat
),其中包含频道信息及其显示位置(即城市)。
我面临的问题是当我重复第二个ng-repeat
:
<table class="table table-condensed" ng-init="nitsCh = [objsCh[$index].nit]">
这应该得到第一个ng-repeat的$ index并创建一个新的数组,其中显示了通道的位置。它确实如此。但是,当我使用这个数组应用第二个ng-repeat时,它无法正常工作。
说我的html看起来像这样(PS:我需要使用索引值而不是objCh.name
,因为我将这些框放在列中)
<div class="box box-solid box-default" ng-repeat="(indexO, objCh) in objsCh track by indexO" ng-if="indexO%4==0 && indexO<=10">
<div class="box-header">
<div class="pull-left">
<img src="dist/img/channels/{{ objsCh[indexO].pic }}" data-toggle="tooltip" title="" data-original-title="Alterar logo do canal">
<h3 class="box-title">{{ objsCh[(indexO)].name }}</h3>
</div>
<div class="box-tools pull-right">
<button class="btn btn-box-tool" data-toggle="tooltip" title="" data-original-title="Adicionar ou Remover NIT"><i class="fa fa-plus"></i></button>
</div>
</div>
<div class="box-body">
<table class="table table-condensed" ng-init="nitsCh = [objsCh[indexO].nit]">
<tbody>
<tr>
<th style="width: 10px">#</th>
<th>Nit</th>
</tr>
<tr ng-repeat="(indexN,nitCh) in nitsCh track by indexN">
<td>{{ objsCh[(indexO + 1)].nit[indexN].num }}</td>
<td>{{ objsCh[(indexO + 1)].nit[indexN].name }}</td>
</tr>
</tbody>
</table>
</div>
</div>
JS文件如下所示:
var app = angular.module('appApp', []);
app.controller('ctrlApp', function($scope, $http) {
var url = "includes/exibChNit.php";
$http.get(url).success(function(response) {
all = response;
$scope.objsCh = all.channels;
});
});
json文件(php创建)看起来像这样:
{
"channels": [{
"id": "1",
"sid": "1",
"name": "Channel",
"pic": "channel.jpg",
"crc32": "A1g423423B2",
"special": "0",
"url": "",
"key": "",
"type": "",
"city": [{
"num": "1",
"name": "S�o Paulo"
}, {
"num": "2",
"name": "Rio de Janeiro"
}]
}, {
"id": "2",
"sid": "2",
"name": "CHannel 1",
"pic": "channel.jpg",
"crc32": "A1F5534234B2",
"special": "0",
"url": "",
"key": "",
"type": "",
"city": [{
"num": "1",
"name": "S�o Paulo"
}, {
"num": "2",
"name": "Rio de Janeiro"
}]
}]
}
当我尝试这个时它起作用:
<table class="table table-condensed" ng-init="nitsCh = [objsCh[($parent.$index + 1)].nit]">
但是我无法这样做,因为json节点将是动态的。
提前致谢!
答案 0 :(得分:36)
ng-repeat
创建了自己的$scope
。
因此,对于内部ng-repeats,您可以访问$parent.$index
,其中$parent
是当前重复块的父范围。
例如:
<ul ng-repeat="section in sections">
<li>
{{section.name}}
</li>
<ul>
<li ng-click="loadFromMenu($parent.$index)" ng-repeat="tutorial in section.tutorials">
{{tutorial.name}}
</li>
</ul>
</ul>