Question

所以我有两个环境Test and Prod。

我在两种环境中都有相同的表格。两个表都有很多列。

如何检查一个表中是否有任何列不在另一个表中，而不单独比较它们？对此有任何技巧或提示吗？

我试过

SELECT t.name as table_name,
SCHEMA_NAME(schema_ID) as schema_name,
c.name as column_name
from sys.tables as t
inner join sys.columns c on t.object_ID = c.object_ID
WHERE t.name like '834daily%'

但它没有返回任何东西。

两个SQL数据库都在不同的服务器上，.100是测试版，.110是prod。

我确信在SQL中有一种简单的方法可以做到这一点，但不确定最好的方法。我也做了一些事情，比如写出CREATE TABLE声明，但我永远不能让它们并排进行直接比较。这可能吗？

Answer 1

你可能会这样做：

LINKED SERVER：

--find your both test and prod server name by running query below
select * from sys.servers


--query to find column name that exists in one environment and not in other
--replace SERVERNAME AND DATABASENAME as needed
SELECT COLUMN_NAME
FROM SERVERNAME.DATABASENAME.INFORMATION_SCHEMA.COLUMNS prod 
WHERE TABLE_NAME = 'YourTableName'
AND NOT EXISTS (
SELECT 1
FROM SERVERNAME.DATABASENAME.INFORMATION_SCHEMA.COLUMNS test
WHERE prod.TABLE_NAME = test.TABLE_NAME);

非连接服务器：

--replace SERVERNAME AND DATABASENAME to match yours
SELECT COLUMN_NAME
FROM (
    SELECT COLUMN_NAME
        ,TABLE_NAME
    FROM OPENROWSET('SQLNCLI', 'Server=SERVERNAME;Trusted_Connection=yes;', 
    'SELECT COLUMN_NAME,TABLE_NAME FROM DATABASENAME.INFORMATION_SCHEMA.COLUMNS 
     WHERE TABLE_NAME = ''YOURTABLENAME''')
    ) AS prod
WHERE NOT EXISTS (
        SELECT 1
        FROM SERVERNAME.DATABASENAME.INFORMATION_SCHEMA.COLUMNS test
        WHERE prod.TABLE_NAME = test.TABLE_NAME
        );

比较不同环境中的表以进行列更改

1 个答案: