我将揭露我现在正在做的事情,以及之后,我想用NInject做些什么。
类:
内核公开了几种方法:
object method(IIdentity identity)
-----------------------
public List<Domain.Channel> getChannels(Domain.Identity.IIdentity identity) {...}
内核包含多个存储的身份,根据每个上下文我需要做一件事或另一件事。 在这种情况下,我的上下文在方法内,上下文键是标识参数值。根据这个,我需要得到一个ApiClient实例。
实际上,我是使用Kernel类的Dictionary属性执行此操作的:
private Dictionary<Domain.Identity.IIdentity, LEST.Client.ApiClient> lests;
然后我初始化。
foreach (Domain.Identity.IIdentity identity in this.identities)
{
LEST.Client.ApiClient lest = new LEST.Client.ApiClient();
lest.configure(identity.ClientId, identity.Username, identity.Password);
this.lests.Add(identity, lest);
}
所以,当我需要根据身份获得具体的ApiClient对象时:
public List<Domain.Channel> getChannels(Domain.Identity.IIdentity identity)
{
LEST.Client.ApiClient current_lest;
this.lests.TryGetValue(identity, out current_lest);
if (current_lest != null)
{
...
}
我想使用NInject来做。我创建了一个模块,以便创建自己的绑定。问题是我不知道如何创建这样的自定义上下文。
我很感激你的帮助。
谢谢大家。
修改
我抽象了一个基本的核心课程,总结了我的解释。
public class Core
{
private IList<IIdentity> identities;
private Ninject.IKernel kernel;
public Core()
{
this.identities = new List<IIdentity>();
}
public void initialize()
{
this.kernel = new Ninject.StandardKernel(new LestModule());
}
public void openSession(IIdentity identity)
{
ApiClient client = this.kernel.Get<ApiClient>();
}
public void doSomething(IIdentity identity)
{
ApiClient client = this.kernel.Get<ApiClient>();
client...
}
public void closeSession(IIdentity identity)
{
ApiClient client = this.kernel.Get<ApiClient>();
this.kernel.Release(client);
}
}
模块是:
public class LestModule : Ninject.Modules.NinjectModule
{
public override void Load()
{
this.Bind<ApiClient>().ToProvider(new CustomProvider());
this.Bind<IIdentity>().To<Identity>();
}
}
public class CustomProvider : IProvider<ApiClient>
{
public object Create(IContext context)
{
//context data???
// How to obtain current IIdentity on here?
object d = context;
return new ApiClient("", "", "");
}
public System.Type Type
{
get { return typeof(ApiClient); }
}
}
ApiClient的抽象
public class ApiClient
{
private string username;
public string Username
{
get { return username; }
set { username = value; }
}
private string client_id;
public string ClientId
{
get { return client_id; }
set { client_id = value; }
}
private string passwd;
public string Passwd
{
get { return passwd; }
set { passwd = value; }
}
public ApiClient(string client_id, string username, string password)
{
this.client_id = client_id;
this.username = username;
this.passwd = password;
}
}
所以,我喜欢这样:
答案 0 :(得分:0)
我已经实现了这个。
现在正在运作。
public class LestModule : Ninject.Modules.NinjectModule
{
public override void Load()
{
this.Bind<LEST.Client.ApiClient>().ToProvider<LEST.Client.ApiClient>(new ApiClientProvider());
}
}
public class ApiClientProvider : Ninject.Activation.IProvider<LEST.Client.ApiClient>
{
private System.Collections.Generic.Dictionary<Domain.Identity.LESTIdentity, LEST.Client.ApiClient> lests;
public ApiClientProvider()
{
this.lests = new System.Collections.Generic.Dictionary<Domain.Identity.LESTIdentity, LEST.Client.ApiClient>();
}
public object Create(Ninject.Activation.IContext context)
{
Ninject.Parameters.IParameter identity_parameter = context.Parameters.FirstOrDefault(p => p.Name == "identity");
Domain.Identity.LESTIdentity identity = (Domain.Identity.LESTIdentity)identity_parameter.GetValue(context, null);
LEST.Client.ApiClient current_client = null;
this.lests.TryGetValue(identity, out current_client);
if (current_client == null)
{
current_client = new LEST.Client.ApiClient();
current_client.configure(...);
this.lests.Add(identity, current_client);
}
return current_client;
}
...
}
为了根据身份获取实例:
public void createChannel(Domain.Identity.ClientIdentity client_identity, Domain.Identity.UserIdentity user_identity, Domain.Channel channel)
{
LEST.Client.ApiClient client = NinjectServiceLocator.Instance.Kernel.Get<LEST.Client.ApiClient>(new Ninject.Parameters.Parameter("identity", new Domain.Identity.LESTIdentity(user_identity.Id, user_identity.Name, client_identity.Id, client_identity.Name), true));
client.ChannelsApiP.Create(AutoMapper.Mapper.Map<Domain.Channel, LEST.Model.ChannelDTO>(channel));
}
你有什么关系?