php count array multidimensional with loop by value

Question

您好，感谢您的帮助，这是我的代码。

我有一个 number.txt 文件，如下所示：

5041655 5492272 1109
5041657 5492274 1109
5041656 5492273 1109
5041060 5491807 1102
5041656 5492273 1102
5036664 5486420 1101

我在php文件中加载 number.txt ，如下所示：

<?

$file = fopen("number.txt","r");
while(($get = fgetcsv($file, 1000, ",")) !== FALSE){

    $data = preg_split("/[\t]/", $get[0]);
    $username = $data[2];

    print_r($username);
}

?>

但我不知道如何打印如下：

number : 1109 is number1
number : 1109 is number2
number : 1109 is number3
number : 1102 is number1
number : 1102 is number2
number : 1101 is number1

谢谢。

Answer 1

试试这个

<?php
$array = array(
     1109,
     1109,
     1109,
     1102,
     1102,
     1101
);

for($i = 0; $i < count($array); $i++)
{
    echo "number : ".$array[$i]." is number".$i + 1 ."<br />";
}
?>

更新1

答案更新为您的问题。

<?php

$file = fopen("number.txt","r");

$i = 1;
while(($get = fgetcsv($file, 1000, ",")) !== FALSE)
{
    //$data = preg_split("/[\t]/", $get[0]);
    $data = explode(" ", $get[0]);

    $username = $data[2];

    //print_r($username);
    echo "number : $username is number".$i++."<br />";
}

?>

输出

更新2

<?php

$file = fopen("number.txt","r");

//$i = 1;
$numbers = array();
while(($get = fgetcsv($file, 1000, ",")) !== FALSE)
{
    //$data = preg_split("/[\t]/", $get[0]);
    $data = explode(" ", $get[0]);

    $numbers[] = $data[2];
    //$username = $data[2];

    //print_r($username);
    //echo "number : $username ";//$i++."<br />";
}

$numbers = array_count_values($numbers);
foreach($numbers as $key => $val)
{
    echo "number : $key found $val times<br />";
}

?>

更新2的输出

最终答案

<?php

$file = fopen("number.txt","r");

$numbers = array();
while(($get = fgetcsv($file, 1000, ",")) !== FALSE)
{
    //$data = explode(" ", $get[0]);
    $data = preg_split("/[\t]/", $get[0]);

    $numbers[] = $data[2];
    $number = array_count_values($numbers);
    echo "number : $data[2] number ".$number[$data[2]]."<br />";
}

?>

最终输出

Answer 2

为了您的理解

 <?php
     $i = 1;
     foreach($array as $arr) {
       echo "<p>number : $arr[0] is number $i</p>";
       $i++;
     }

Answer 3

在线之间阅读 - 我认为这就是你所追求的。 此解决方案“计算”相同值的数量，如果它们相同则递增值，或将计数器设置回1。

$array = array(
     Array ( 0 => 1109 ),
     Array ( 0 => 1109 ),
     Array ( 0 => 1109 ),
     Array ( 0 => 1102 ),
     Array ( 0 => 1102 ),
     Array ( 0 => 1101 )
);

$i = 1;

foreach($array as $a){

    foreach($a as $k => $v){

        $i = ($prevValue == $v) ? $i+1 : 1;

        echo "<br>number : $v is number $i";

        $prevValue = $v;

    }

}