Question

我有Panel这个结构

<asp:Panel ID="Custom" Visible="false" runat="server">
    Search: 
<asp:TextBox ID="TextBox1" AutoPostBack="true" runat="server">
</asp:TextBox>
    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
<asp:ListBox ID="ListBox1"  Visible="true" runat="server" DataSourceID="UserSearchSource" SelectionMode="Multiple" DataTextField="username" DataValueField="username"></asp:ListBox>
<asp:SqlDataSource ID="UserSearchSource" runat="server" ConnectionString="<%$ ConnectionStrings:fscauth %>" SelectCommand="SELECT [user] FROM [table] WHERE ([user] LIKE '%' + @username + '%') ORDER BY [username]">
<SelectParameters>
<asp:ControlParameter ControlID="TextBox1" Name="user" PropertyName="Text" Type="String" />
</SelectParameters>
</asp:SqlDataSource>
<br /> <br /> <asp:Button ID="Button2" CausesValidation="false" runat="server" Text="Add" OnClick="Button2_Click" />
</asp:Panel>

所以，我有一个TextBox在数据库中扮演用户搜索者的角色，结果显示在ListBox上。在添加Button_Click时，它会将结果填充到DataTable中，该Gridview用作DataTable数据源。我想要实现的是，每次单击“添加”按钮时，不仅会将结果添加到protected void Button2_Click(object sender, EventArgs e) { List<string> lista = getUserList(ListBox1); DataTable dt = new DataTable(); DataRow dr = null; dt.Columns.Add(new DataColumn("user", typeof(string))); for (int i = 0; i < lista.Count;i++ ) { dr = dt.NewRow(); dr["user"] = lista[i].ToString(); dt.Rows.Add(dr); } ViewState["CurrentTable"] = dt; GridView1.Visible = true; GridView1.DataSource = dt; GridView1.DataBind(); Button3.Visible = true; Button1.Visible = true; MessagePanel.Visible = true; }，而且不会删除以前的结果列表。目前我一直在使用的是：

getuserlist

和protected List<string> getUserList(ListBox lb) { List<string> li = new List<string>(); // List<string> lista = (List<string>)Session["list"]; foreach (ListItem l in lb.Items) { if (l.Selected) { li.Add(l.Text); } } Session["list"] = li; List<string> lista = (List<string>)Session["list"]; return lista; }函数：

<form name="myForm" novalidate ng-controller="MainController as vm">
    <div>
        <input type="text" ng-model="vm.id" name="idInput" required>
        <input type="email" ng-model="vm.email" name="emailInput" required>
        <input type="text" ng-model="vm.output" name="output">
    </div>
</form>

我不太确定我能想达到的目标是什么，但是如果有人可以帮助我，那就太棒了！

Answer 1

您需要更改此行

 DataTable dt = new DataTable();

而不是创建新表，你应该得到现有的表

 DataTable dt = GridView1.DataSource as DataTable;

表示获取已分配的gridview的数据源并在其中添加行而不是每次都创建新表

将结果添加到数据集而不删除先前的行

1 个答案: