Question

我有多个选择选项。

<select name="uid" multiple>
     <option value="001">001</option>
     <option value="002">002</option>
     <option value="003">003</option>
</select>

我想在mysql中查询数据。例如，如果我选择uid 001＆amp; 003，然后是uid 001＆amp;的数据。将显示003。

$get_uid = $_GET['uid'];
$query = mysql_query("SELECT * FROM t_user WHERE uid = '$uid'");

那么如何设置查询多值选择。

Answer 1

试试此代码

$get_uid = $_GET['uid']; //array
if (count($get_uid) > 0) {
    $get_uid = implode(',', $get_uid); //string;
    $query = mysql_query("SELECT * FROM t_user WHERE uid IN ($get_uid)");
}

Answer 2

试试这个......

$get_uid = implode(",",$_GET['uid']);
$query = mysql_query("SELECT * FROM t_user WHERE uid IN ($get_uid)");

http://www.tutorialspoint.com/mysql/mysql-in-clause.htm

基于多重选择的PHP查询数据

2 个答案: