这里用于验证我使用onsubmit事件。 但任何它不起作用。 我只想检查文本框是否为空。
<!DOCTYPE html>
<html>
<head>
<title>temple3</title>
<link rel="stylesheet" type="text/css" href="temple3css.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
</head>
<body>
<div id="popup-content" class='container'>
<div id="container1">
<form id="form" class="form" onsubmit="return validateForm()">
<h1>Feedbak Form</h1>
<div class="content">
<div class="intro"></div>
<div id="section0" >
<div class="field roption">
<input type="radio" name="view" value="public" checked="checked"> <span>Public</span>
<input type="radio" name="view" value="private" ><span>Private</span>
</div>
<div class="field category">
<label for>Category:</label>
<select class="dropDownCate" autofocus>
<option value="bug">Bug</option>
<option value="1">1</option>
<option value="2">2</option>
</select>
</div>
<div class="field message">
<label for="Comments">Comments:</label>
<textarea id="comments" name="Comments" placeholder='Your Feedback Here!' autofocus></textarea>
</div>
<div class="field">
<label for="Email">Email</label>
<input type="email" id="email" name="Email" placeholder="example@stevens.edu(optional)" autofocus>
</div>
<div class="field"><input type="submit" id="submit-feedback-button" autofocus></div>
</div>
</div>
</form>
</div>
</div>
<div id="popup-overlay-bg"> </div>
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script>
function validateForm(){
var texbox=document.getElementById("comments").value;
if(texbox == "") {
document.getElementById("comments").focus();
// document.getElementById("comments").style.border = "1px solid #ff0000";
return false;
}
}
$(document).ready(function(){
$("#feedback-button").click(function(){
openfeedbackform();
});
$("#popup-overlay-bg").click(function(){
closefeedbackform();
});
$("#submit-feedback-button").click(function(){
// closefeedbackform();
});
$(window).resize(function(){
updatefeedbackform();
});
$("#submit-feedback-button").click(function(){
var category=$(".dropDownCate").val();
var roption=$('input:radio[name=view]:checked').val();
var message=$("#comments").val();
var email=$("#email").val();
$.ajax({
type: "POST",
url: "feedback.php",
data: "category="+category+ "&roption="+roption+ "&message="+message+ "&email="+email,
success:function(result)
{
if(result=="true"){
$("#form").hide();
$("#container1").html("<h3>Thank you for your feedback We will get back to you ASAP</h3> ");
}
else{
$("#form").hide();
$("#container1").html("<h3> database error </h3>");
}
}
});
return false;
});
});
function openfeedbackform(){
$("#popup-content").find('input:text').val('');
$("#popup-content").fadeIn();
$("#popup-overlay-bg").fadeIn();
updatefeedbackform();
}
function updatefeedbackform(){
$popup=$("#popup-content");
var top = "50px";
var left = ($(window).width() - $popup.outerWidth()) / 2;
$popup.css({
'top' : top,
'left' : left
});
}
function closefeedbackform(){
$("#popup-content").fadeOut();
$("#popup-overlay-bg").fadeOut();
}
</script>
</body>
</html>
之前我使用相同的表格验证。但我不知道为什么它不在这里工作。我试图调试,但功能尚未调用。
答案 0 :(得分:2)
问题是你在按钮点击事件中进行ajax提交,而不是在表单提交中。
在提交事件处理程序之前触发单击处理程序,因此验证没有任何效果。
解决方案是使用表单提交事件处理程序进行验证和下面给出的ajax调用,然后就不需要像onsubmit="return validateForm()"
$("#form").submit(function () {
if (validateForm() === false) {
return false;
}
var category = $(".dropDownCate").val();
var roption = $('input:radio[name=view]:checked').val();
var message = $("#comments").val();
var email = $("#email").val();
$.ajax({
type: "POST",
url: "feedback.php",
data: "category=" + category + "&roption=" + roption + "&message=" + message + "&email=" + email,
success: function (result) {
if (result == "true") {
$("#form").hide();
$("#container1").html("<h3>Thank you for your feedback We will get back to you ASAP</h3> ");
} else {
$("#form").hide();
$("#container1").html("<h3> database error </h3>");
}
}
});
return false;
});