Question

我之前从未使用过课程，而且我正在尝试大致了解它们如何使用我在下面的代码示例。我有问题引用我为一个类定义的名称之一。我只是希望程序在输入选项2时打印出列表中存储的员工姓名和工资列表，但它给出了以下错误：

追踪（最近一次通话）：文件＆＃34; C：\ Scott Glenn \ Misc \ classes.py＆＃34;，第31行，in 员工[I] .displayEmployee AttributeError：＆＃39; str＆＃39;对象没有属性＆＃39; displayEmployee＆＃39;

class Employee:
    'Common base class for all employees'
    empCount = 0

    def __init__(self, name, salary):
        self.name = name
        self.salary = salary
        Employee.empCount += 1

    def displayCount(self):
        print "Total Employee %d" % Employee.empCount

    def displayEmployee(self):
        print "Name : ", self.name,  ", Salary: ", self.salary

def AddNewEmployee():
    NewEmployee = raw_input("What is the Employees name: ")
    employees.append(str(NewEmployee))
    NewEmployeeSalary = raw_input("What is the Employees salary: ")
    NewEmployee = Employee(NewEmployee, NewEmployeeSalary)
    return employees
#=============================================================================
employees=[]
while(1):
    print'Welcome to the Employee Database!'
    option = raw_input('Please select 1 to add new employee or 2 to      display all current employees: ')
    if option=='1':
        employees.append(AddNewEmployee())
    if option=='2':
        for i in range(0,len(employees)):
            employees[i].displayEmployee

Answer 1

AddNewEmployee功能错误。当您想要返回自定义类型list的单个对象时，它会返回单string的{{1}}。

应该更像这样：

Employee

此外，您尝试访问def AddNewEmployee(): #string variable to hold name NewEmployeeName = raw_input("What is the Employees name: ") #why make a list? you are appending the result of this function to that list #employees.append(str(NewEmployee)) #plus this is adding the employee before he's even been created NewEmployeeSalary = raw_input("What is the Employees salary: ") #construct using name string and salary string NewEmployee = Employee(NewEmployeeName, NewEmployeeSalary) return NewEmployee #return Employee object (to be appended later)作为类的字段，而不是方法。字段不具有括号和方法（因此它们可以接受参数，但在这种情况下，括号为空，因为没有参数传递）。

最后，请注意displayEmployee()会返回raw_input，因此如果您希望自己string成为float，则应该转为NewEmployeeSalary。（现在它是string。）

Answer 2

我已在下面更新了您的代码。我看到你遇到的主要问题是你使用“员工”作为全球性并且两次追加它。我将它移出AddNewEmployee（）函数并返回新员工，然后将其附加到'employees'

你也没有打电话给'.displayEmployees' 注意我添加到最后的括号。

我希望这有帮助！

class Employee(object):
    'Common base class for all employees'
    empCount = 0

    def __init__(self, name, salary):
        self.name = name
        self.salary = salary
        Employee.empCount += 1

    def displayCount(self):
        print "Total Employee %d" % Employee.empCount

    def displayEmployee(self):
        print "Name : ", self.name, ", Salary: ", self.salary


def AddNewEmployee():
    NewEmployee = raw_input("What is the Employees name: ")
    NewEmployeeSalary = raw_input("What is the Employees salary: ")
    NewEmployee = Employee(NewEmployee, NewEmployeeSalary)
    return NewEmployee


# =============================================================================

if __name__ == "__main__":

    employees = []
    while True:
        print'Welcome to the Employee Database!'
        option = raw_input(
            'Please select 1 to add new employee or 2 to display all current employees: ')
        if option == '1':
            employees.append(AddNewEmployee())
        if option == '2':
            for i in range(0, len(employees)):
                employees[i].displayEmployee()

Python在函数

2 个答案: