Question

我试图将用C＃编写的以下密钥生成方法重写为其Ruby等价物：

        private static byte[] CreateKey(string password, int length)
        {
            var salt = new byte[] { 0x01, 0x02, 0x23, 0x34, 0x37, 0x48, 0x24, 0x63, 0x99, 0x04 };

            const int Iterations = 1000;
            using (var rfc2898DeriveBytes = new Rfc2898DeriveBytes(password, salt, Iterations))
                return rfc2898DeriveBytes.GetBytes(length);
        }

我正在使用PBKDF2实施。这是我的Ruby代码：

def create_key password, length
    salt_a = [0x01, 0x02, 0x23, 0x34, 0x37, 0x48, 0x24, 0x63, 0x99, 0x04]
    salt = salt_a.pack('C*') # Think here there is something to change
    iterations = 1000
    derived_b = PBKDF2.new do |p| 
      p.password = password
      p.salt = salt
      p.iterations = iterations
      p.key_length = length
      p.hash_function = OpenSSL::Digest::SHA1
    end
    derived_b.bin_string # and here too
end

为了工作，这两个方法应该返回相同的输出。问题是我无法弄清楚如何做到这一点。 PBKDF2实现将salt作为String，但C＃采用字节数组......我认为问题出在那里。

Answer 1

如果您可以使用最新版本的OpenSSL，那么这对我有用：

SALT = [ 0x94, 0x67, 0x16, 0xe6, 0x20, 0xd4, 0x56, 0x46, 0x67, 0x56, 0x46, 0x56, 0x23 ].pack("c*")
PBKDF2_ITERATIONS = 1000

def create_key(password, length)
  OpenSSL::PKCS5::pbkdf2_hmac_sha1(password, SALT, PBKDF2_ITERATIONS, length)
end

从C＃加密密钥派生到Ruby（PBKDF2）

1 个答案: