最有效的MySQL(面试查询)

时间:2015-07-16 18:27:58

标签: mysql select

最近在接受采访时,我遇到了以下问题:

我有一个包含以下表的数据库(为了这个例子,让我们说这些表是有意义的):

  • 用户(id,name,cc_id)
  • 信用卡式(ID)
  • 电影(身份证,姓名)
  • 购买(movie_id,cc_id)

我想找到购买电影“黑暗骑士”的顾客的名字。

我的回答是:

SELECT name FROM User AS u
    INNER JOIN CreditCard AS cc ON u.id = cc.id
    INNER JOIN Purchase AS p ON p.movie_id = 
        (SELECT id FROM Movie AS m WHERE m.name = "Dark Knight") AND cc.id = p.cc_id

除了语法之外,我想知道这是否是解决此问题的更有效方法。

2 个答案:

答案 0 :(得分:3)

最好只加入movie表,不要加入creditcard

SELECT u.name 
FROM `User` AS u
INNER JOIN Purchase AS p ON p.cc_id = u.cc_id
INNER JOIN movie m on p.movie_id = m.id
WHERE m.name = 'Dark Knight'

答案 1 :(得分:1)

SELECT name from User as u
    JOIN CreditCards as cc on cc.id = u.cc_id
    JOIN Purchase AS p ON p.cc_id = c.id
    JOIN Movie AS m on m.id = p.movie_id
WHERE m.name = 'Dark Night';