Question

我在python中用两个文件创建了一个代码。
从main.py调用一个功能屏幕，它有一些单选按钮。

错误是我运行代码＆amp;主屏幕打开，如果点击“确定” 按钮然后它工作正常。但是，如果按关闭按钮关闭窗口，则会出现错误。

[code]

Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Python27\lib\lib-tk\Tkinter.py", line 1536, in __call__
    return self.func(*args)
File "E:\main_menu.py", line 51, in suicide
    self.screen.destroy()
File "C:\Python27\lib\lib-tk\Tkinter.py", line 1898, in __getattr__
    return getattr(self.tk, attr)
AttributeError: screen
[/code]

main.py [代码]

import main_menu

while True:
    val = main_menu.screen()
    if(1 == val):
        //do something
    elif(2 == val):
        //do something
    elif(3 == val):
        //do something

    #print(val)    
[/code]

main_screen.py [代码]

from Tkinter import *
import Tkinter



class menu1(Tkinter.Tk):

    def __init__(self, master):
        Tkinter.Tk.__init__(self,master)
        self.master = master

        self.protocol("WM_DELETE_WINDOW", self.suicide)

        #clear value
        self.val1 = 1

        #default selection
        self.v = IntVar()
        self.v.set(1)

        #create a label
        self.x1 = Label(self,text="Choose a function:",justify = CENTER,padx = 100)
        self.x1.pack()

        #first radiobutton
        self.x2 = Radiobutton(self,text="text1",padx = 100,variable=self.v,value=1)
        self.x2.pack(anchor=W)

        #second radiobutton
        self.x3 = Radiobutton(self,text="text2",padx = 100,variable=self.v,value=2)      
        self.x3.pack(anchor=W)

        #third radiobutton
        self.x4 = Radiobutton(self,text="text3",padx = 100,variable=self.v,value=3)    
        self.x4.pack(anchor=W)

        #fourth radiobutton
        self.x5 = Radiobutton(self,text="text4",padx = 100,variable=self.v,value=4)    
        self.x5.pack(anchor=W)

        #create button
        self.x6 = Button(self,text="OK",command=self.submit)    
        self.x6.pack()

    def submit(self):
        self.val1 = self.v.get()
        self.destroy()

    def suicide(self):
        self.val1  = 0
        self.screen.destroy()        

def screen():
    #create a root object
    root = menu1(None)
    root.title("Option")
    root.geometry("480x320")
    root.mainloop()
    return root.val1      
[/code]

Answer 1

self.screen.destroy()会引发异常，因为您没有self.screen。

我认为您只需要self.destroy()，就像上面submit()方法

一样

蟒蛇;屏幕退出错误

1 个答案: