Question

我遇到了与另一个实体保持@OneToOne关系的实体的问题。我们最近使用Spring 4和Hibernate 4升级到Java 8，所以我确信有一些注释或配置已经改变。

相关代码

PermitState.java：

@Entity
@Table(schema = "dbo", name = "PermitState")
public class PermitState implements Serializable {

private String oid;
private Permit permit;
private Integer invoiced;
private Integer used;
private Integer ordered;
private String permitId;


@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "PERMITID")
public Permit getPermit() {
    return permit;
}

@Id
@Column(name = "PERMITID", nullable = true, length = 8,insertable = false,updatable = false)
public String getPermitId() {
    return permitId;
}

... more getters and setters (irrelevant)

Permit.java：

@Entity
@Table(schema = "dbo")
public class Permit {

private String permitid;
private PermitState permitState;


...some more attributes, irrelevant


@Id
@Column(name = "PERMITID", length = 8)
public String getPermitid() {
    return permitid;
}

@OneToOne(mappedBy="permit", cascade=CascadeType.ALL,fetch = FetchType.LAZY)
public PermitState getPermitState() {
    return permitState;
}

堆栈跟踪

Caused by: org.hibernate.exception.GenericJDBCException: could not insert: [dao.srs.model.PermitState]
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:54)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:124)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3099)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3521)
    at org.hibernate.action.internal.EntityInsertAction.execute(EntityInsertAction.java:88)
    at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:395)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:387)
    at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:303)
    at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:349)
    at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:56)
    at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1195)
    at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:404)
    at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:101)
    at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:175)
    at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:75)
    at org.springframework.orm.jpa.JpaTransactionManager.doCommit(JpaTransactionManager.java:515)
    ... 65 more
Caused by: com.microsoft.sqlserver.jdbc.SQLServerException: The index 6 is out of range.
    at com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDriverError(SQLServerException.java:171)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setterGetParam(SQLServerPreparedStatement.java:700)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setValue(SQLServerPreparedStatement.java:709)
    at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.setString(SQLServerPreparedStatement.java:1034)
    at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.setString(NewProxyPreparedStatement.java:963)
    at org.hibernate.type.descriptor.sql.VarcharTypeDescriptor$1.doBind(VarcharTypeDescriptor.java:57)
    at org.hibernate.type.descriptor.sql.BasicBinder.bind(BasicBinder.java:93)
    at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:284)
    at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:279)
    at org.hibernate.type.ComponentType.nullSafeSet(ComponentType.java:343)
    at org.hibernate.persister.entity.AbstractEntityPersister.dehydrateId(AbstractEntityPersister.java:2835)
    at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2804)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3076)
    ... 78 more

正如您所看到的，PermitState实体与Permit（通过PERMITID，它是Permit中的PK）和一个名为PermitId的字段有关系，该字段应该是连接的Permit ID。这似乎不起作用，似乎它试图插入所有6个属性，即使不应该将Permit插入数据库。我尝试使用@Transient在PermitState中注释Permit，但后来我得到一个AnnotationException：

Caused by: org.hibernate.AnnotationException: Unknown mappedBy in: dao.srs.model.Permit.permitState, referenced property unknown: dao.srs.model.PermitState.permit

任何帮助将不胜感激！

更新为了澄清，数据库只有5个字段--OID，PERMITID，INVOICED，USED和ORDERED - 这就是为什么我在考虑尝试插入Permit实体。当我们使用Java 7，Spring 3，hibernate-annotations 3.3.1.GA和hibernate-entitymanager 3.3.2.GA时，完全相同的代码没有修改。我们现在使用Java 8，Spring 4和Hibernate core + entitymanager + ehcache 4.2.19。

Answer 1

在我看来，从异常情况来看，你在尝试@Transient的同时仍然拥有@OneToOne和@JoinColumn。这真的没有意义，因为你告诉Hibernate你想自己处理它，它也应该处理它。

另外我发现你们在PermitState中拥有Permit实体和permitId有点令人困惑。您告诉它您不想更新permitId，但仍然将其用作连接列？

我建议删除permitId，并且只允许PermitState中的Permit实体。如果您愿意，您仍然可以使用getPermitId方法，而是将其视为agregate。

如果所有其他方法都失败，请尝试并记录Hibernate生成的SQL以查看发生了什么。也许粘贴它让我们看。

Answer 2

我想我解决了。我仍然不完全确定为什么会这样，但确实如此：

我从PermitState.java中删除了PermitId（String属性），而是使用PermitState中的Permit权限中的PermitId。

看起来像这样：

Permit.java：

private String permitid;
private PermitState permitState;

@OneToOne(mappedBy="permit", cascade=CascadeType.ALL,fetch = FetchType.LAZY)
public PermitState getPermitState() {
    return permitState;
}

PermitState.java

private Permit permit;

@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "PERMITID")
public Permit getPermit() {
    return permit;
}

感谢Martin和Bilbo的帮助。

持久化实体时的SQLServerException - 索引超出范围

2 个答案: