以下是我的CREATE TABLE
脚本:
CREATE TABLE Person
(
ID INT Primary Key Identity (1,1),
LastName nVarchar (20) not NULL,
FirstName nVarchar (20) not NULL,
MiddleName nVarchar (20),
BirthDate DateTime not NULL,
Age INT not NULL,
Check (Age18)
);
CREATE TABLE Department
(
ID INT Primary Key Identity (1,1),
DepartmentName nVarchar (50) Unique,
DepartmentCode nVarchar (20) Unique,
IsActive Bit Default (1)
);
CREATE TABLE Employee
(
ID INT Primary Key Identity (1,1),
PersonId INT Foreign Key REFERENCES Person,
DepartmentId INT Foreign Key REFERENCES Department,
Salary Decimal (18,2),
Check (Salary10000),
IsActive Bit Default (1)
);
以下是我的INSERT
脚本:
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Dela Cruz','Juan',NULL,01/01/199,22)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Dela Cerna','Pedro','Juan',11/01/1993,21)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Villaflores','Rachel','Diacoma',10/7/1990,24)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Abendan','Marnell',NULL,03/15/1989,25)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Oplado','Aiza','Tapayan',11/18/1993,21)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Loreto','Desire','Talingting',06/10/1993,21)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Magbanua','Prince Laurence','Rallos',05/25/1992,22)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Locsin','Franz Cyril',NULL,02/14/1993,21)
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age)
VALUES ('Dela Pena','Precious',NULL,01/01/199,21)
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive)
VALUES ('ITDepartment','ItDept',1)
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive)
VALUES ('EngineeringDepartment','EDept',1)
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive)
VALUES ('ComputerScienceDepartment','CSDept',1)
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive)
VALUES ('InformationSystemDepartment','ISDept',1)
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive)
VALUES ('BusinessAdministrationDepartment','BADept',1)
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive)
VALUES ('ElementaryDepartment','ElemDept',1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (1,2,12000,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (2,4,10001,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (3,6,13000,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (4,1,25000,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (5,3,15000,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (6,5,10002,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (7,1,56000,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (8,4,14000,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (9,6,15900,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (2,4,12300,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (4,1,13500,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (6,3,14300,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (8,5,12500,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (1,2,11460,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (3,4,10910,1)
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive)
VALUES (5,6,10001,1)
以下是我的选择脚本:
SELECT
Person.LastName, Department.DepartmentName
FROM
Person, Department
FULL OUTER JOIN
Employee ON Employee.PersonId = Employee.DepartmentId
这是不对的结果。我不知道这是对的。这是我第一次做JOINS。
Dela Cruz BusinessAdministrationDepartment
Dela Cerna BusinessAdministrationDepartment
Villaflores BusinessAdministrationDepartment
Abendan BusinessAdministrationDepartment
Oplado BusinessAdministrationDepartment
Loreto BusinessAdministrationDepartment
Magbanua BusinessAdministrationDepartment
Locsin BusinessAdministrationDepartment
Dela Pena BusinessAdministrationDepartment
Dela Cruz ComputerScienceDepartment
Dela Cerna ComputerScienceDepartment
Villaflores ComputerScienceDepartment
Abendan ComputerScienceDepartment
Oplado ComputerScienceDepartment
Loreto ComputerScienceDepartment
Magbanua ComputerScienceDepartment
Locsin ComputerScienceDepartment
Dela Pena ComputerScienceDepartment
我在计算机科学系停留了,因为它太长了。我怎么做到这一点?请帮忙。谢谢! :)
答案 0 :(得分:2)
Select p.LastName, d.DepartmentName
From Employee As e
Join Person As p On e.PersonId = p.Id
JOin Department As d On e.DepartmentId = d.ID
答案 1 :(得分:1)
SELECT Person.LastName, Department.DepartmentName
FROM Employee INNER JOIN Person
ON Employee.PersonId = Person.ID
INNER JOIN Department
ON Employee.DepartmentId = Department.ID