从输出的db结果创建php shuffle的问题

Question

我在按下提交按钮时尝试创建PHP shuffle。我没有看到任何像我正在尝试做的例子，因为我将把输出的结果用于其他事情。截至目前，此代码已被破解，我无法通过此行的解析错误Parse error: syntax error, unexpected ')' ...

foreach ($shuffle_row) {

我的方法有什么问题？

$con = mysqli_connect("localhost", "ROOT", "", "DB");
$shuffle_run = mysqli_query($con,"SELECT * FROM users WHERE `group`= 3");
if( $shuffle_numrows > 0) {
    while($shuffle_row = mysqli_fetch_assoc($shuffle_run)){
        $shuffle_id = $shuffle_row['id'];
        $shuffle_firstname = $suffle_row['firstname'];
        $shuffle_lastname = $shuffle_row['lastname'];
        $shuffle_username = $shuffle_row['username'];
        $shuffle_email = $shuffle_row['email'];

        if ($shuffle_firstname == true) {
            echo $shuffle_firstname . $shuffle_lastname;
        } else {
            echo "No users have been registered yet.";
        };
    }
}

if(isset($_POST['shuffle']))  {
    $shuffle_row = array();
    shuffle($shuffle_row);
    foreach ($shuffle_row) {
        echo $shuffle_firstname . " " . $shuffle_lastname;
    }
}
}
?>
<input type="submit" value="Shuffle" name="shuffle">