Question

如果我有这个：

SubMenuList=new object[]
{
    new 
    { 
        transKey = "PERSONAL_INFORMATION",
        stateName="account.personalinformation", 
        displayUrl = "/account/personalinformation" 
    },
    new 
    { 
        tranKey = "NOTIFICATIONS",
        stateName = "account.notificationsettings",
        displayUrl = "/account/notifications"
    }
}

我可以以某种方式向此添加if语句并说出例如：

if (something != null)
{
    new
    {
        transKey = "PERSONAL_INFORMATION", 
        stateName="account.personalinformation", 
        displayUrl = "/account/personalinformation" 
    }
}

Answer 1

为此，最好使用List<Object>：

var list = new List<object>
{
    new 
    { 
        transKey = "PERSONAL_INFORMATION",
        stateName="account.personalinformation", 
        displayUrl = "/account/personalinformation" 
    }
};
if (something != null)
{
    list.Add(new
             {
                 tranKey = "NOTIFICATIONS",
                 stateName = "account.notificationsettings",
                 displayUrl = "/account/notifications"
             });
}

如果你想获得一个数组，你可以在链接上调用ToArray()：

SubMenuList = list.ToArray();

最好在这里引入非匿名类型，因为这些对象具有相同的结构，没有上下文，很难猜出为什么不使用命名类型。

Answer 2

您可以使用@DavidArno建议的实际类型列表，并在something != null添加新项目到列表中。

您还可以使用匿名类型：

var list = new[]
{
    new 
    { 
        transKey = "PERSONAL_INFORMATION",
        stateName="account.personalinformation", 
        displayUrl = "/account/personalinformation" 
    },
    new 
    { 
        transKey = "NOTIFICATIONS",
        stateName = "account.notificationsettings",
        displayUrl = "/account/notifications"
    }
}.ToList()

if (something != null)
{
    list.Add(new
    {
        transKey = "PERSONAL_INFORMATION", 
        stateName="account.personalinformation", 
        displayUrl = "/account/personalinformation" 
    });
}

如果您不需要访问匿名类型的成员（例如list[0].transKey）或者使用反射是可以的，那么Alex的回答可能更适合您的问题。

如何在匿名类中添加if语句？

2 个答案: