Question

我试图生成一个简单的下拉列表（Laravel 5），其中每个选项的值是我的businesslocations表行的ID，显示的文本由多列数据组成（address_1，address_2），城市）从每一行开始。

在我的控制器中

public function create()
{       
    $businesslocations = Businesslocation::where('businesslocations.business_id', '=', \Auth::user()->business_id)->get();

    return view('client.create')->with(['businesslocations' => $businesslocations]);
}

这是我在create.blade.php

中的位置

{!! Form::label('businesslocation_id', 'Business location:') !!}
@foreach($businesslocations as $key => $businesslocation)
    {!! Form::select('businesslocation_id',  $businesslocations, null, ['class' => 'form-control']) !!}
@endforeach

显示值0：

<label for="businesslocation_id">Business location:</label>
<select class="form-control" id="businesslocation_id" name="businesslocation_id"><option value="0">{&quot;id&quot;:&quot;3&quot;,&quot;business_id&quot;:&quot;7&quot;,&quot;address_1&quot;:&quot; &quot;,&quot;address_2&quot;:&quot; &quot;,&quot;city&quot;:&quot; &quot;,&quot;created_at&quot;:&quot;2015-07-13 15:59:19&quot;,&quot;updated_at&quot;:&quot;2015-07-13 15:59:19&quot;}</option></select>

我正在寻找像这样的值=＆＃34; id＆＃34;并显示text =＆＃34; address_1 address_2 city＆＃34;对于每个选项。不确定到达那里的语法。

<label for="businesslocation_id">Business location:</label>
<select class="form-control" id="businesslocation_id" name="businesslocation_id"><option value="1">Business location 1 - address_1 address_2 city</option><option value="2" selected="selected">Business location 2 - address_1 address_2 city</option></select>

Answer 1

使用常规HTML生成选项，效果很好。

@Override

public void onCreate(Bundle savedInstanceState) {

// Request email address

GraphRequest.newMeRequest(

   loginResult.getAccessToken(),new GraphRequest.GraphJSONObjectCallback() {

   public void onCompleted(JSONObject me, GraphResponse response) {

      Log.d("TEST", response.toString());
      if (response.getError() != null) {
        // handle error
      } else {
        Log.d("TEST", me.toString());
        String email = me.optString("email");
        String id = me.optString("id");
        Log.d("TEST", "Email:" + email);
     }
  }
}).executeAsync();

LoginButton authButton =(LoginButton) findViewById(R.id.login_button);

List<String> permissions = new ArrayList<>();

permissions.add("public_profile");

permissions.add("email");

authButton.setReadPermissions(permissions);

}

Answer 2

查询构建器可以使用＆＃34;列表＆＃34;方法 - 所以如果你使用返回business_id的sql作为＆＃34; id＆＃34;和地址1 +地址2 +城市为＆＃34;名称＆＃34;

SELECT `businesslocation_id` as `id`, 
CONCAT_WS(" ", `address1`, `address2`) AS `name` FROM `businesslocation`

然后返回一个列表 - 类似于：

$businesslocations = Businesslocation::where('businesslocations.business_id', '=', \Auth::user()->business_id)
->get()
->lists('name','id'); 
(This is untested)

然后，Eloquent将知道如何处理该名称，如果您坚持下去，则相应地显示它：

{!! Form::select('businesslocation',  $businesslocations, null, ['id'=> 'businesslocation','class' => 'form-control']) !!}

所以基本上如果你想用Laravel方式做，你需要将name和id传递给select下拉列表。

也就是说，您还可以为您的商家位置模型添加一个功能：

public function getFullAddressAttribute()
{
    return $this->business->address1 . ' ' . $this->business->address2 . ' ' . $this->business->city;
}

然后

$businesslocations = Businesslocation::where('businesslocations.business_id', '=', \Auth::user()->business_id)
->get()
->lists('fullAddress','id');

希望能引导你朝着正确的方向前进！请注意，我还没有测试过上面的代码。

表单选择选项，无法获取值并显示正确的文本

2 个答案: