Question

如何将包含随机字符的String转换为有意义的整数数组？

int MAX= 27;

我有字符串input="-3,5,7-12,20-16,21-";

如何将其转换为[1,2,3,5,7,8,9,10,11,12,20,19,18,17,16,21,22,23... MAX ]

之类的整数数组

（不使用任何输入功能，如input.split（＆＃34;，＆＃34;））

package Others;

import java.util.ArrayList;
import java.util.List;

public class convertToInteger {

    public static void main(String[] args) {
        String numbers = "-3,5,7-12,20-16,21-";
        char c[] = numbers.toCharArray();
        System.out.println(c.length);
        List<Character> list = new ArrayList<Character>();

        for (int i = 0; i < c.length; i++) {
            // System.out.println(!(c[i] == '3') + "" + c[i]);

            if (numbers.charAt(i) == '-' || numbers.charAt(i) == ',') {

            }
            else {
                int temp = c[i];
                int actual = (int) c[i];

                if (temp == actual) {
                    System.out.println("Integer" + c[i]);
                    if (!((c[i + 1]) == ',')) {

                    }
                }
                // System.out.println(c[i]);
            }
        }
        System.out.println(list);
    }
}

Answer 1

如果我理解你的问题，你可以按照

这样做

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Pattern;

public class Test {

    private static final String NUMBER_ONLY_REGEX = "\\d+";

    private static final Pattern REGEX = Pattern.compile("(,|-)");

    public static void main(final String[] args) {
        final String numbers = "-3,5,7-12,20-16,21-";
        final String[] matcher = REGEX.split(numbers);
        final List<Integer> integerList = new ArrayList<Integer>();

        for (int i = 0; i < matcher.length; i++) {
            if(matcher[i].matches(NUMBER_ONLY_REGEX)) {
                integerList.add(Integer.parseInt(matcher[i].trim()));
            }
        }
        System.out.println(integerList);
    }
}

具有不同charcters到整数Array的字符串

1 个答案: