如何在SQL Server中将hh：mm：ss转换为秒超过24小时

Question

我有一个表名tblAttend，其中一个名为WorkHrs的列的数据类型为varchar。

简单选择查询的结果是

我总结这个列的值，并在几秒钟内得到结果，我的查询是

select sum(DATEDIFF(SECOND, '0:00:00', WorkHrs )) 
from tblAttend

并显示此输出：

现在的问题是，当WorkHrs的总和大于24小时时，它会引发错误：

你有什么建议可以解决这个问题？提前致谢

Answer 1

我已经实现了以下功能，以便在我的项目管理中使用它：

/****** Object:  UserDefinedFunction [dbo].[Seconds]    Script Date:     10/6/2017 12:00:22 PM ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
/*
select [dbo].[Seconds]('24:00:00'),(24*3600)
select [dbo].[Seconds]('102:56:08'),(102*3600+56*60+8)
*/
ALTER FUNCTION [dbo].[Seconds] (@Time as varchar(50))
RETURNS int
BEGIN
declare @S int, @H int
set @H=cast(SUBSTRING(@Time,1,CHARINDEX(':',@Time)-1) as int)
IF @H<24
set @S=DATEDIFF(SECOND, '0:00:00', @Time)
ELSE BEGIN
    set @H=@H-23
    set @Time = '23'+SUBSTRING(@Time,CHARINDEX(':',@Time),LEN(@Time)-2)
    set @S = (@H*3600)+DATEDIFF(SECOND, '0:00:00', @Time)
END
RETURN @S
END

Answer 2

试试这个：

SELECT DATEDIFF(SECOND, CONVERT(DATE,GETDATE()), GETDATE())

Answer 3

我认为您可以将时间的各个部分（小时，分钟和秒）隔离开，而不是总结所需的内容，请看一下：

declare @tbl table(WorkHrs VARCHAR(8))
insert into @tbl(WorkHrs) values ('02:29:11')
insert into @tbl(WorkHrs) values ('25:00:11')
-- Sum in minutes
SELECT TRY_CAST(([HOURS] * 60) + [MINUTES] + ([SECOND] / 60) AS INT) as TotalInMinutes
FROM (
SELECT 
    -- Use this aproach to get separated values 
    SUBSTRING(WorkHrs,1,CHARINDEX(':',WorkHrs)-1) AS [HOURS],
    SUBSTRING(WorkHrs,4,CHARINDEX(':',WorkHrs)-1) AS [MINUTES],
    SUBSTRING(WorkHrs,7,CHARINDEX(':',WorkHrs)-1) AS [SECOND] -- probably you can ignore this one
    FROM @tbl
)
tbl
-- Or try to sum in seconds
SELECT TRY_CAST(([HOURS] * 3600) + ([MINUTES] * 60) + [SECOND] AS INT) as TotalInSeconds
FROM (
SELECT 
    -- Use this aproach to get separated values 
    SUBSTRING(WorkHrs,1,CHARINDEX(':',WorkHrs)-1) AS [HOURS],
    SUBSTRING(WorkHrs,4,CHARINDEX(':',WorkHrs)-1) AS [MINUTES],
    SUBSTRING(WorkHrs,7,CHARINDEX(':',WorkHrs)-1) AS [SECOND]
    FROM @tbl
)
tbl

它将像这样返回给您：

我希望它可以帮助

Answer 4

您可以尝试这样：

SELECT Sec=SUM((DATEPART(HOUR,column name)*3600)+(DATEPART(MINUTE,column name)*60)+(DATEPART(Second,column name)))
FROM [TableName]

Answer 5

尝试：

DECLARE @DURATION TIME = '01:43:24'

SELECT DATEDIFF(SECOND, '1/1/1900', CONVERT(DATETIME, @DURATION))

Answer 6

您可以简单地使用TIME_TO_SEC函数：

SELECT TIME_TO_SEC(WorkHrs) FROM tblAttend;