请您查看this demo并告诉我为什么我无法将.slideDown()
函数添加到所选元素的父元素后输入动态div的过程中?
$(function () {
$("button").on("click", function () {
$(".err").hide();
var elem = $(this);
elem.parent().after('<div class="alert alert-danger err" role="alert">Thanks For Adding</div>').slideDown("slow");
});
});
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@import url("https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css");
body {
padding:50px;
}
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.3/jquery.min.js"></script>
<div class="well well-sm box">
<button class="btn btn-default btn-block" type="submit">Add Box</button>
</div>
<div class="well well-sm box">
<button class="btn btn-default btn-block" type="submit">Add Box</button>
</div>
<div class="well well-sm box">
<button class="btn btn-default btn-block" type="submit">Add Box</button>
</div>
<div class="well well-sm box">
<button class="btn btn-default btn-block" type="submit">Add Box</button>
</div>
<div class="well well-sm box">
<button class="btn btn-default btn-block" type="submit">Add Box</button>
</div>
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答案 0 :(得分:3)
这应该有效:)
$(function () {
$("button").on("click", function () {
var elem = $(this);
var $div = $('<div/>',{class: 'alert alert-danger err',role: 'alert'}).hide().text('Thanks For Adding');
$div.insertAfter(elem.parent());
$div.slideDown("slow");
});
});