使用XML

Question

我有一个XML文件

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!DOCTYPE labels SYSTEM "label.dtd">
   <labels _FORMAT ="BARCODE" _QUANTITY="1" _PRINTERNAME="P1">

        <label>
             <variable name= "PRTNUM">234243242</variable>
             <variable name= "QUANTY">004342</variable>
             <variable name= "PONUMB">844463541</variable>
             <variable name= "SERIAL">DZ12</variable>
             <variable name= "REV">234235</variable>
             <variable name= "UNITS">234235</variable>
        </label>

     </labels>

我已解析的

，即＆lt;＆gt; ......标签之间的包含 例如。 004342仅读取004342数据＆amp;其他人被忽视了。 因此整个解析后的数据已经保存到另一个文件名parsed.txt中，看起来像

234243242
004342
844463541
DZ12
234235
234235

这个解析后的数据我必须与其他文件（barcode.dpl）合并

c0001

f260

L

D11

H30

R0000

C0040

1X1100000100010B300300003003

181100202900027Part No

181100202900097[PRTNUM]

1e5504002400030B

1X1100002300010L300003

191100202000030Quantity

191100202000080[QUANTY]

1e5504001500040B

1X1100001400010L300003

1X1100001400150L003090

191100202000170P.O.No

191100202000220[PONUMB]

1e5504001500180B

191100201200030Supplier

1e3304000700030B

1X1100000600010L300003

181100200300030Serial

181100200300090[SERIAL]

171100300900190Rev

171100300300190[REV]

171100300900240Units

171100300300240[UNITS]

1X1100000100180L003130

Q0001

E

解析后的数据将放在[PRTNUM]，[QUANTY]，[PONUMB]等处。 ＆安培;该文件看起来像....

c0001

f260

L

D11

H30

R0000

C0040

1X1100000100010B300300003003

181100202900027Part No

181100202900097234243242

1e5504002400030B

1X1100002300010L300003

191100202000030Quantity

191100202000080004342

1e5504001500040B

1X1100001400010L300003

1X1100001400150L003090

191100202000170P.O.No

191100202000220844463541

1e5504001500180B

191100201200030Supplier

1e3304000700030B

1X1100000600010L300003

181100200300030Serial

181100200300090DZ12

171100300900190Rev

171100300300190234235

171100300900240Units

171100300300240234235

1X1100000100180L003130

Q0001

E

所以实际上我的问题是当它从条形码文件中检测到[....]时解析数据位置，而不管xml＆amp;中给出的标记名称是什么。条形码文件...如果我将[QUANTY]放在[PRTNUM]的位置，它将放置相同的数据234243242（实际上为[PRTNUM]）。 如何使我的程序能够从barcode.txt文件中读取[...]内的数据。然后将解析文件中的相应数据放在该位置。

我的c代码是......

#include<stdlib.h>
#include<stdio.h>
#include<conio.h>
#include<DIR.h>
#include<string.h>

int main()
{

  clrscr();

  int a[1];

  char cBuffer[50] = {0};

  char ch, cSkipdata;

  FILE* fPtr;

  FILE* fPparse;

  FILE* fPin;

  FILE* fPout;

  char* Ptr;




      getcwd(cBuffer, 100);
      printf("The current directory is %s\n\n",cBuffer);
      fPtr = fopen("sample.xml", "r");                    /* Open XML file*/
      fPparse = fopen("parse.txt","w");


      if(fPtr)
      {


    printf("The file is\n\n");
    scanf("%c",&a[1]);
                            // look for test between > and <
    cSkipdata=1;
    while ((ch = getc(fPtr)) != EOF)                     /* read character */
    {

           if(ch == '<')
              cSkipdata=1;

           if(!cSkipdata && ch != ' ')
           {

            putchar(ch);
             // fputc(ch ,stdout);
            fputc(ch, fPparse);
           }
                                 /* write character */
    if(ch == '>')

          cSkipdata=0;
   }





  fclose(fPtr);
  fclose(fPparse);

  }

  else

  {

    printf("file can not open\n");

  }

    fPin = fopen("barcode.txt", "r");                 /* Open DPL file*/
    fPout = fopen("final.txt", "w");                  /* Open the output final to save changea*/
    fPparse = fopen("parse.txt","r");

    scanf("%c",&a[1]);
    printf("\n\nfinal.txt is \n");
       cSkipdata = 0;
  while((ch = getc(fPin)) != EOF)
  {


        if(ch == '[')                                                   /* Skip the data if condition is true*/

        {


              int iLine=0;
             cSkipdata = 1;

        while ( (ch = getc(fPparse)) != EOF)            //f read a character
        {
                                  //if newline and we have output data break
             if((ch=='\n')  && (iLine>0) )

            break;                                       // end of line
                                //if not space output character

                if(ch > ' ')
                {
                                  // valid character output
                   iLine++;
                   putchar(ch);
                   fputc(ch, fPout);

                 }
           }

        }



        if(cSkipdata)
        {

         if(ch == ']')

            cSkipdata = 0;



        }


        else
        {

            putchar(ch);
            fputc(ch ,fPout);



        }


  }

           fclose(fPin);
           fclose(fPout);
           fclose(fPparse);







getch();
}