Question

我在我的项目中使用了UICollectionView。我开始以编程方式完成所有这些工作（在swift中）。这是我的代码，它启动并将collectionView添加到屏幕：

GUI

全大写字母变量是我之前创建的常量。

一切顺利，除非我从纵向切换到横向，每行中的项目数量不会改变，但切换到横向时，行中的项目应该比以前更多。

我试图覆盖此功能：

public class Anagram {
    Map<String, HashSet<String>> anagrams = Collections.synchronizedMap(new HashMap<String, HashSet<String>>());
    List<String> glossary;
    AtomicInteger availableProcessors = new AtomicInteger();
    AtomicInteger start = new AtomicInteger();
    AtomicInteger end = new AtomicInterger();  // the end of current part

Anagram(Glossary glossary) {
    this.glossary = new ArrayList<>(glossary.getGlossary());
}

public void findAnagrams() {
    availableProcessors.set(Runtime.getRuntime().availableProcessors());
    end.set(0);
    start.set(0);
    buildAnagramMap();
    // displayAnagrams();   // not used in this part of code
}

/**
 * Builds map of anagrams
 */
private void buildAnagramMap() {
    System.out.println("Starting build anagrams map at thread " + Thread.currentThread().getName());
    if (glossary != null) {
        ExecutorService executorService = Executors.newCachedThreadPool();
        for (int i = 0; i < availableProcessors.get(); i++) {
            executorService.execute(new Runnable() {
                @Override
                public void run() {
                    System.err.println("Thread " + Thread.currentThread().getName() + " started");
                    end.set(start.get() + glossary.size() / availableProcessors.get());
                    // if not divisible by number of available processors then we add residue to last thread
                    if ((glossary.size() % availableProcessors.get() > 0) &&
                            ((glossary.size() - end.get()) < (glossary.size() / availableProcessors.get()))) {
                        end.set(glossary.size());
                    }
                    for (int i = start.get(); i < end.get(); i++) {
                        String key = sortString(glossary.get(i));
                        HashSet<String> val = anagrams.get(key);
                        if (val == null) {
                            val = new HashSet<>();
                            anagrams.put(key, val);
                        }
                        val.add(glossary.get(i));
                        start.set(start.get() + 1);
                    }
                    System.err.println("Completed thread " + Thread.currentThread().getName());
                }
            });
        }
        executorService.shutdown();
        while (!executorService.isTerminated()) {
            try {
                executorService.awaitTermination(Long.MAX_VALUE, TimeUnit.NANOSECONDS);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
    } else {
        System.err.println("Glossary doesn't exist");
    }
    System.out.println(Thread.currentThread().getName() + " successfully ended");
}

虽然有效但是在旋转iPhone时需要大约半秒钟来填充行（它以一种丑陋的方式缓慢地完成工作）。

我该如何解决？

UICollectionView从纵向到横向

0 个答案: