我的程序没有语法错误，但我无法获得最终的平均＃right

Question

我的程序没有语法错误，我可以输入所有值，但我无法得到正确的最终平均数。任何人都可以帮我找出问题吗？ 以下是我输入的内容：

1. 你有多少名员工？ 4
2. 员工＃1缺席多少天？ 4
3. 缺少员工＃2多少天？ 2
4. 缺少员工＃3多少天？ 1
5. 缺少员工＃4多少天？ 3

最终答案应为： 2.5

这是我使用的代码：

import java.util.Scanner;

class Number {
    public static void main(String[] args) {
        int numEmployee = Number.workers();
        int absentSum = Number.totaldays(numEmployee);
        double averageAbsent = Number.average(numEmployee, absentSum);
    }

    public static int workers() {
        int number = 0;
        Scanner input = new Scanner(System.in);

        while (number > 0 || number < 0 || number == 0) {
            System.out.println("How many employees do you have?");
            number = input.nextInt();
            if (number >= 0) {
                return number;
            } else {
                System.out
                        .println("You can not enter a negative               number."
                                + " Please enter another number.");
            }
        }
        return number;
    }

    public static int totaldays(int numEmployee) {
        int absentDays = 0;
        int absentSum = 0;

        for (int employName = 1; employName <= numEmployee; employName++) {
            System.out.println("How many days was Employee #" + employName
                    + " absent?");
            Scanner input = new Scanner(System.in);
            absentDays = input.nextInt();
            while (absentDays < 0) {
                System.out.println("You can not enter a negative number."
                        + " Please enter another number.");
                System.out.println("How many days was Employee #" + employName
                        + " absent?");
                absentDays = input.nextInt();
            }
            absentSum += absentDays;
        }

        return absentSum;
    }

    public static double average(int numEmployee, int absentSum) {
        double averageAbsent = (double) absentSum / (double) numEmployee;
        System.out.println("Your employees averaged " + averageAbsent
                + " days absent.");
        return averageAbsent;
    }
}