我正在使用cURL进行自定义HTTP标头请求。但是如何让PHP显示标题?
<?php
$ch = curl_init();
curl_setopt($ch, CURLOPT_HTTPHEADER, array('my_key: 12345'));
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLINFO_HEADER_OUT, true);
$response = curl_exec($ch);
curl_close($ch);
echo $response;
echo "<br><br>";
if($_SERVER['my_key']=='12345'){
echo 'Key is OK';
} else {
echo 'Key is wrong';
}
// also tried!
print_r($_COOKIE);
var_dump (curl_getinfo($ch));
?>
答案 0 :(得分:0)
我想你的简单方法可能是guzzle
。你可以这样做:
$client = new GuzzleHttp\Client();
$res = $client->get('https://api.github.com/user', ['auth' => ['user', 'pass']]);
echo $res->getStatusCode(); // "200"
echo $res->getHeader('content-type'); // 'application/json; charset=utf8'
echo $res->getBody(); // {"type":"User"...'
更多信息in docs。
另外,您可以查看this solution。
如果您真的想要获取请求,而不是响应标头,则应尝试以下代码:
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://www.google.com/');
curl_setopt($ch, CURLINFO_HEADER_OUT, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec($ch);
curl_getinfo ($ch);
/*[
"url" => "http://www.google.com/",
"content_type" => "text/html; charset=UTF-8",
"http_code" => 302,
"header_size" => 267,
...
"redirect_url" => "http://www.google.com.ua/?gfe_rd=cr&ei=-fClVYDfA9eEtAH65oGQAQ",
"request_header" => "GET / HTTP/1.1\r\nHost: www.google.com\r\nAccept: * /*\r\n\r\n"
]*/