尝试挂起异步请求的连接时出现Jersey错误

时间：2015-07-15 02:44:52

标签： java servlets jersey servlet-filters

我正在做一个关于使用泽西暂停asynch请求的小测试，但我得到一个错误。让我告诉你我想要做什么，以及服务器启动和运行的方式只是这个请求失败了：

Path("/json/metallica")
public class JSONService {

    @GET
    @Path("/test")
    @Produces(MediaType.APPLICATION_JSON)
    public void getAsynchHealthyTracks(@Suspended AsyncResponse asyncResponse){

        HealthService.getInstance().getHealththyTracks(asyncResponse);
    }

}

当我在tomcat上从我的本地主机调用它时，我收到以下错误：

 HTTP Status 500 - javax.ws.rs.ProcessingException: Attempt to suspend a connection of an asynchronous request failed in the underlying container.

type Exception report

message javax.ws.rs.ProcessingException: Attempt to suspend a connection of an asynchronous request failed in the underlying container.

description The server encountered an internal error that prevented it from fulfilling this request.

exception

javax.servlet.ServletException: javax.ws.rs.ProcessingException: Attempt to suspend a connection of an asynchronous request failed in the underlying container.
    org.glassfish.jersey.servlet.WebComponent.service(WebComponent.java:391)
    org.glassfish.jersey.servlet.ServletContainer.service(ServletContainer.java:381)
    org.glassfish.jersey.servlet.ServletContainer.service(ServletContainer.java:344)
    org.glassfish.jersey.servlet.ServletContainer.service(ServletContainer.java:221)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)
root cause

javax.ws.rs.ProcessingException: Attempt to suspend a connection of an asynchronous request failed in the underlying container.
    org.glassfish.jersey.server.model.ResourceMethodInvoker.apply(ResourceMethodInvoker.java:312)
    org.glassfish.jersey.server.model.ResourceMethodInvoker.apply(ResourceMethodInvoker.java:103)
    org.glassfish.jersey.server.ServerRuntime$1.run(ServerRuntime.java:271)
    org.glassfish.jersey.internal.Errors$1.call(Errors.java:271)
    org.glassfish.jersey.internal.Errors$1.call(Errors.java:267)
    org.glassfish.jersey.internal.Errors.process(Errors.java:315)
    org.glassfish.jersey.internal.Errors.process(Errors.java:297)
    org.glassfish.jersey.internal.Errors.process(Errors.java:267)
    org.glassfish.jersey.process.internal.RequestScope.runInScope(RequestScope.java:297)
    org.glassfish.jersey.server.ServerRuntime.process(ServerRuntime.java:254)
    org.glassfish.jersey.server.ApplicationHandler.handle(ApplicationHandler.java:1028)
    org.glassfish.jersey.servlet.WebComponent.service(WebComponent.java:372)
    org.glassfish.jersey.servlet.ServletContainer.service(ServletContainer.java:381)
    org.glassfish.jersey.servlet.ServletContainer.service(ServletContainer.java:344)
    org.glassfish.jersey.servlet.ServletContainer.service(ServletContainer.java:221)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)

我的web.xml文件中已经有<async-supported>true</async-supported>，这是web.xml文件的内容：

 <!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app>
  <display-name>Archetype Created Web Application</display-name>


    <servlet>
        <servlet-name>jersey-servlet</servlet-name>
        <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
        <init-param>
            <param-name>jersey.config.server.provider.packages</param-name>
            <param-value>com.example.ema,com.fasterxml.jackson.jaxrs.json</param-value>
            <async-supported>true</async-supported>
            <load-on-startup>1</load-on-startup>
        </init-param>

        <init-param>
            <param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
            <param-value>true</param-value>
        </init-param>

    </servlet>
    <servlet-mapping>
        <servlet-name>jersey-servlet</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>



</web-app>

健康服务本身只是构建一个pojo对象，应该将其作为json发回。无论如何，这是服务：

public class HealthService {
private static HealthService instance = null;
protected HealthService() {
    // Exists only to defeat instantiation.
}
public static HealthService getInstance() {
    if(instance == null) {
        instance = new HealthService();
    }
    return instance;
}

public void getHealthyTracks(AsyncResponse asyncResponse){


    try {
        Thread.sleep(3000);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }


    Track track = new Track();
    track.setSinger("micheal jackson");
    track.setTitle("thriller");

    asyncResponse.resume(track);
}

}

我提出了一个破发点，甚至没有达到最初的球衣要求。服务器停止了。我的最终目标是睡几秒钟然后发回回复。

更新：这是现在的web.xml照片：

enter image description here

2 个答案:

答案 0 :(得分：0)

我想出了这个问题。标签“true”不应该放在init params部分。它应该放在web.xml文件中的servlet标记内。我的web.xml现在看起来像这样：

<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:web="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">

  <display-name>Archetype Created Web Application</display-name>


    <servlet>
        <servlet-name>jersey-servlet</servlet-name>
        <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
        <async-supported>true</async-supported>
        <init-param>
            <param-name>jersey.config.server.provider.packages</param-name>
            <param-value>com.example.ema,com.fasterxml.jackson.jaxrs.json</param-value>

            <load-on-startup>1</load-on-startup>
        </init-param>

        <init-param>
            <param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
            <param-value>true</param-value>
        </init-param>

    </servlet>
    <servlet-mapping>
        <servlet-name>jersey-servlet</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>



</web-app>

答案 1 :(得分：0)

需要对web.xml内的Servlet配置进行小的更改

<servlet>
    <servlet-name>jersey-servlet</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>com.javapapers.webservices.rest.jersey</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
    <async-supported>true</async-supported>
</servlet>

观察“异步支持”元素的位置/嵌套，它已作为子元素定位在“ servlet”元素下。

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