我正在克隆JFreeChart,然后使用setSeriesVisible()方法禁用其中一个系列。该系列没有出现。但是,图例项仍会出现。如何使图例项不显示。我究竟做错了什么?
这是我的代码:
package test;
import java.awt.Color;
import java.util.logging.Level;
import java.util.logging.Logger;
import org.jfree.chart.ChartFactory;
import org.jfree.chart.ChartPanel;
import org.jfree.chart.JFreeChart;
import org.jfree.chart.axis.NumberAxis;
import org.jfree.chart.plot.PlotOrientation;
import org.jfree.chart.plot.XYPlot;
import org.jfree.chart.renderer.xy.XYLineAndShapeRenderer;
import org.jfree.data.xy.XYDataset;
import org.jfree.data.xy.XYSeries;
import org.jfree.data.xy.XYSeriesCollection;
import org.jfree.ui.ApplicationFrame;
import org.jfree.ui.RefineryUtilities;
public class Test2 extends ApplicationFrame {
public Test2(final String title) {
super(title);
try {
final XYDataset dataset = createDataset();
final JFreeChart chart = createChart(dataset);
JFreeChart tempChart = (JFreeChart) chart.clone();
tempChart.getXYPlot().getRenderer().setSeriesVisible(1, false, true);
final ChartPanel chartPanel = new ChartPanel(tempChart);
chartPanel.setPreferredSize(new java.awt.Dimension(500, 270));
setContentPane(chartPanel);
} catch (CloneNotSupportedException ex) {
Logger.getLogger(Test2.class.getName()).log(Level.SEVERE, null, ex);
}
}
private XYDataset createDataset() {
final XYSeries series1 = new XYSeries("First");
series1.add(1.0, 1.0);
series1.add(2.0, 4.0);
series1.add(3.0, 3.0);
series1.add(4.0, 5.0);
series1.add(5.0, 5.0);
series1.add(6.0, 7.0);
series1.add(7.0, 7.0);
series1.add(8.0, 8.0);
final XYSeries series2 = new XYSeries("Second");
series2.add(1.0, 5.0);
series2.add(2.0, 7.0);
series2.add(3.0, 6.0);
series2.add(4.0, 8.0);
series2.add(5.0, 4.0);
series2.add(6.0, 4.0);
series2.add(7.0, 2.0);
series2.add(8.0, 1.0);
final XYSeries series3 = new XYSeries("Third");
series3.add(3.0, 4.0);
series3.add(4.0, 3.0);
series3.add(5.0, 2.0);
series3.add(6.0, 3.0);
series3.add(7.0, 6.0);
series3.add(8.0, 3.0);
series3.add(9.0, 4.0);
series3.add(10.0, 3.0);
final XYSeriesCollection dataset = new XYSeriesCollection();
dataset.addSeries(series1);
dataset.addSeries(series2);
dataset.addSeries(series3);
return dataset;
}
private JFreeChart createChart(final XYDataset dataset) {
final JFreeChart chart = ChartFactory.createXYLineChart(
"Line Chart Demo 6", // chart title
"X", // x axis label
"Y", // y axis label
dataset, // data
PlotOrientation.VERTICAL,
true, // include legend
true, // tooltips
false // urls
);
chart.setBackgroundPaint(Color.white);
final XYPlot plot = chart.getXYPlot();
plot.setBackgroundPaint(Color.lightGray);
plot.setDomainGridlinePaint(Color.white);
plot.setRangeGridlinePaint(Color.white);
final XYLineAndShapeRenderer renderer = new XYLineAndShapeRenderer();
renderer.setSeriesLinesVisible(0, false);
renderer.setSeriesShapesVisible(1, false);
plot.setRenderer(renderer);
final NumberAxis rangeAxis = (NumberAxis) plot.getRangeAxis();
rangeAxis.setStandardTickUnits(NumberAxis.createIntegerTickUnits());
return chart;
}
public static void main(final String[] args) {
final Test2 demo = new Test2("Line Chart Demo 6");
demo.pack();
RefineryUtilities.centerFrameOnScreen(demo);
demo.setVisible(true);
}
}
答案 0 :(得分:0)
如您所知,默认情况下,Java clone()
方法执行“浅拷贝”,这意味着它不会克隆对象的每个字段(它只是复制对象的引用)他们)。因此,除非他们在文档中明确地解释它,否则clone()
方法在被开发人员覆盖时会做什么并不清楚。在目前的情况下,我会说it is still a bit ambiguous:
克隆对象,并负责监听器。注意:调用者应在克隆图上注册自己的监听器。
所以我不确定Plot
对象,渲染器,数据集,轴,图例等会发生什么。
我的建议:不要使用clone()
。创建需要复制的对象的新实例,这样您就可以精确控制哪些对象是唯一的,哪些对象是兄弟对象。希望传奇与可见系列不一致的问题也会消失。