用于传递URL中提供的数据的视图而不是映射

时间:2015-07-14 21:44:52

标签: python django url django-views

我有一个Django项目结构,如下所示:

siteDirectory
    -manage.py
    -mySite
        -__init.py
        -settings.py
        -urls.py (1)
        -public
            -__init__.py
            -urls.py (2)
            -app1
                -models.py
                -views.py
                -urls.py (3)
            -app2
            -app3
            -urls.py

(为简洁起见,省略了一些文件。)

我已经成功运行了我的网站,我的模型按计划运行。然后我去设置一个URL方案,我可以给出这样的URL:localhost/app1/5其中5是模型对象的ID。这类似于Django教程(https://docs.djangoproject.com/en/1.8/intro/tutorial03/)的“编写更多视图”部分。但是,当我实现它时,我收到404错误,并且我的URL模式未在我的文件中定义。这些是我拥有的URL文件(它们与结构中相应的文件编号匹配)

urls.py(1)

from public import urls as public_urls
from django.conf.urls import include, url
from django.contrib import admin

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),

    # Public-facing site
    url(r'', include(public_urls))
]

urls.py(2)

from app1 import urls as app_one_urls
from app2 import views as app_two_views
from app3 import views as app_three_views

# URLs
urlpatterns = [
    url(r'^app1$', include(app_one_urls)),
    url(r'^app2$', app_two_views.main)
    url(r'^app3$', app_three_views.main),
]

urls.py(3)

from django.conf.urls import url
from . import views


urlpatterns = [
    url(r'^$', views.main, name='index'),
    url(r'^(?P<someObject_id>[0-9]+)/$', views.someObject, name='someObject'),
]

我可以成功访问我的所有应用,但只有someObject GET不起作用。是什么导致了这个404错误?

0 个答案:

没有答案