使用Apache
,我们可以执行以下操作:
<VirtualHost *:80>
ServerAdmin webmaster@localhost
DocumentRoot /var/www/app1/public
<Directory />
Options +Indexes +FollowSymLinks +MultiViews
AllowOverride FileInfo
Require all granted
</Directory>
Alias /app2 "/var/www/app2/public"
<Directory "/var/www/app2/public">
DirectoryIndex index.php
Options +Indexes +FollowSymLinks +MultiViews
AllowOverride All
Require all granted
</Directory>
ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/
<Directory "/usr/lib/cgi-bin">
AllowOverride None
Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch
Order allow,deny
Allow from all
</Directory>
ErrorLog ${APACHE_LOG_DIR}/error.log
# Possible values include: debug, info, notice, warn, error, crit, alert, emerg.
LogLevel warn
CustomLog ${APACHE_LOG_DIR}/access.log combined
</VirtualHost>
所以,在这种方法中,我有两个不同的应用程序:
www.mydomain.com/something
www.mydomain.com/app2/login
两者都是使用Laravel(PHP Framework)开发的,需要接收QUERY STRING
才能工作。
我想转移到Nginx
,目前我的配置是这样的:
server {
listen 80;
server_name host.com;
root /var/www/app1/current/public;
index index.php;
charset utf-8;
# App 1
location / {
try_files $uri $uri/ /index.php?$query_string;
}
location ~ ^/index\.php$ {
fastcgi_split_path_info ^(.+\.php)(/.+)$;
fastcgi_pass 127.0.0.1:9000;
fastcgi_index index.php;
include fastcgi_params;
fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
fastcgi_intercept_errors off;
fastcgi_buffer_size 16k;
fastcgi_buffers 4 16k;
}
location = /favicon.ico { access_log off; log_not_found off; }
location = /robots.txt { access_log off; log_not_found off; }
access_log off;
error_log /var/log/nginx/app.log error;
sendfile off;
client_max_body_size 100m;
location ~ /\.ht {
deny all;
}
}
app1
(根应用程序)运行正常。问题是:如何在该配置文件中设置app2
?
我试过了:
# App 2
location ^~ /app2 {
alias /var/www/app2/current/public;
try_files $uri $uri/ /index.php?$query_string;
}
但是,没有成功。
答案 0 :(得分:1)
我尝试过几件事。
# App 2
# Possibly no need for regex, this will capture urls
# /app2 and /app2/anything/else
location /app2 {
alias /var/www/app2/current/public;
try_files $uri $uri/ /index.php?$query_string;
}
这可能是您唯一的问题,可能会解决它。
然而!如果仍然存在问题(没有输入文件错误,或者它仍然转到app1),那么我们将/index.php
与try_files
一起使用的复杂因素。这会让它继续到你的location ~ ^/index\.php$ {
区块,这可能会抓错$document_root
。
在这种情况下,我不确定最好是不使用别名,而是使用两个PHP块。希望alias
负责自动更改$documentroot
。
答案 1 :(得分:1)
对于那些不完全理解我想要的人:我需要在同一个域名上托管多个PHP应用程序(没有子域名)。
我终于解决了这个问题。这是我的最终配置:
server {
listen 80 deferred;
server_name server.com;
index index.php;
charset utf-8;
# App 1 (main app)
location / {
root /var/www/app1/current/public;
try_files $uri $uri/ /index.php?$query_string;
error_log /var/log/nginx/app1.notice.log notice;
error_log /var/log/nginx/app1.error.log error;
location ~* ^/index\.php$ {
fastcgi_split_path_info ^(.+\.php)(/.+)$;
fastcgi_pass 127.0.0.1:9000;
fastcgi_index index.php;
include fastcgi_params;
fastcgi_param SCRIPT_FILENAME /var/www/app1/current/public/index.php;
fastcgi_intercept_errors off;
fastcgi_buffer_size 16k;
fastcgi_buffers 4 16k;
}
}
# App 2
location ~* /app2 {
alias /var/www/app2/current/public;
try_files $uri $uri/ /app2/index.php?$query_string;
error_log /var/log/nginx/app2.notice.log notice;
error_log /var/log/nginx/app2.error.log error;
location ~* ^/app2/index\.php$ {
fastcgi_split_path_info ^(.+\.php)(/.+)$;
fastcgi_pass 127.0.0.1:9000;
fastcgi_index index.php;
include fastcgi_params;
fastcgi_param SCRIPT_FILENAME /var/www/app2/current/public/index.php;
fastcgi_intercept_errors off;
fastcgi_buffer_size 16k;
fastcgi_buffers 4 16k;
}
}
# Files
location = /favicon.ico { access_log off; log_not_found off; }
location = /robots.txt { access_log off; log_not_found off; }
# Error
access_log off;
rewrite_log on;
# Disable .htaccess access
location ~ /\.ht {
deny all;
}
}