Question

Installing JMeter runtime
Download the _bin and _lib files
Unpack the archives into the same directory structure
The other archives are not needed to run JMeter.

此代码行正常运行。

首先$connect = mysqli...... $command1 = mysqli.... while($row = mysqli_fetch_array($command1)){ echo $row[]; $command2 = mysqli...... while($row = mysqli_fetch_array($command2)){ echo $row['']; } }
确定第二个while loop直到结束
在第二次结束后，它将返回第一个while loop
重复所有过程，直到条件结束为止。

但是当我添加另一个while condition时，所有逻辑都会下降。

while loop

....按第一，第二和第三回声进行屏幕显示。然后我希望它再次返回$connect = mysqli...... $command1 = mysqli.... while($row = mysqli_fetch_array($command1)){ echo $row[]; $command2 = mysqli..... while($row = mysqli_fetch_array($command2)){ echo $row['']; $command3 = mysqli...... while($row = mysqli_fetch_array($command3)){ echo $row['']; } } }，但它会返回$command2，按回显并停止。

为什么它会返回$command1而不是first while？

有什么区别？

Answer 1

<强>更新

你更好地改变你的代码：

$connect = mysqli...
$command1 = mysqli...
$command2 = mysqli...
$command3 = mysqli...
while( $row1 = mysqli_fetch_array( $command1 ) ){
  while( $row2 = mysqli_fetch_array( $command2 ) ){
    while( $row3 = mysqli_fetch_array( $command3 ) ){
    }
  }
}

我相信这样可以解决问题

连续使用三个while循环

1 个答案: