Question

我试图在Swift中连接两个字符，但它显示错误

二进制运算符不能应用于两个字符操作数。

let a: Character = "A"
let l: Character = "l"

let al = a + l

Swift的字符串支持运算符重载，为什么不使用Character？

Answer 1

如果你真的想要/需要能够'＃34;连接＆＃34; 2 Character(s)使用+运算符，您可以定义此函数。

func + (left:Character, right:Character) -> String {
    return "\(left)\(right)"
}

正如Skrundz在评论中所说，Character的实例只能包含1个字符，因此函数的输出将是String。

现在：

let a : Character = "A"
let b : Character = "B"
let ab = a + b // -> the String "AB"

Answer 2

列出连接两个字符的大多数可能性

let character1: Character = "a"
let character2: Character = "b"

let result = String(character1) + String(character2)
let result = "\(character1)" + "\(character2)"
let result = "\(character1)\(character2)"
let result = "" + [character1, character2]
var result = ""; result += [character1, character2]
var result = ""; result.append(character1); result.append(character2)
var result = [String(character1), String(character2)].joined()

在swift

2 个答案: