XML文件问题中的分页jQuery结果集

时间:2010-06-29 14:09:27

标签: javascript jquery css pagination

我正忙着使用我正在开发的代码来显示10个杂志,这些杂志是从xml文件中提供的。我在某种程度上工作,FF和IE7 + 8不喜欢它,可能因为它说第62行有一个错误 - 是调用数据的核心函数。

这是我的代码:

<!DOCTYPE html>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta name="robots" content="noindex, nofollow" />
<title>Brave Creative - Online Archive</title>
<link rel="stylesheet" href="css/global.css" media="screen" />
<script type="text/javascript" charset="UTF-8" src="js/jquery.js"></script>
<script type="text/javascript">

$(document).ready(function() {

 $.ajax({
    type: "GET",
    url: "issues.xml",
    dataType: "xml",
    success: function(xml) {

    var shelf = $('#shelf-items');
                var startIndex = 0; 
                var howMany = 10; 
                var $issues = $(xml).find('issue'); 
                var totalIssues = $issues.length;
    var numPages = Math.ceil(totalIssues / howMany)

    $('span.issuecount').html(+totalIssues+'&nbsp;Issues - '+numPages+'&nbsp;Pages');

                var displayIssues = function() {
                      var $issuesPaginated = $issues.slice( startIndex , (totalIssues - startIndex) + howMany );
                      $('#shelf-items li').fadeOut(500); 
                      $issuesPaginated.each(function(){
                          var id = $(this).attr('id');
                          var date = $(this).find('date').text();
                          var cover = $(this).find('cover').text();
                          var issue = $(this).find('issuenumber').text();
                          var url = $(this).find('url').text();
                          $('<li id="'+id+'"></li>').html('<a href="'+url+'"><img src="images/covers/'+cover+'" alt="" /></a><br />'+date+' - #'+issue+'').fadeIn(500).appendTo(shelf);
                      });
                }

                $('#prevIssueButton').click(function() {
                    if( startIndex < howMany) {
                        startIndex -= howMany;
                        displayIssues();
                    }else {
      startIndex = 0;
                        displayIssues();
      $('span.error').html('No Issues to Display - You are now on Page 1').fadeIn(300).fadeOut(3000);
                    }
                });
                $('#nextIssueButton').click(function() {
      if( startIndex + howMany <= totalIssues) {
                        startIndex += howMany;
                        displayIssues();
                    }else {
      $('span.error').html('No Issues to Display - You are now on Page 1').fadeIn(300).fadeOut(3000);
                        startIndex = 0;
                        displayIssues();

                    }
                });
                displayIssues().fadeIn(500); 
            }
   }); // end ajax call

}); // end document-ready

</script>
</head>
<body>

<div id="bc-publish"><span></span></div>

<br />

<div id="wrapper">

 <header>
  <h1>Online Archive: <span>FSM</span></h1>
 </header>

    <section id="buttons">

     <a href="#" id="prevIssueButton" title="Toggle Previous Entries">Previous</a>
        <a href="#" id="nextIssueButton" title="Toggle Next Entries">Next</a>

        <span class="error"><a></a></span>

        <div class="clear"></div>

    </section> <!-- /buttons -->

    <section id="shelf">

     <ul id="shelf-items"></ul>

        <div class="clear"></div>

    </section> <!-- /shelf -->
    <br />
    <span class="issuecount"></span>

    <br /><br />

    <span class="logo"><a href="http://www.bravecreative.co.uk" title="Brave Creative"><img src="images/brave-creative-logo.jpg" alt="Brave Creative" /></a></span>
    <span class="address">

     <span>t.</span> 01733 392978 <span>m.</span> 07719442825<br />
  <span>e.</span> tony@bravecreative.co.uk<br />
        4 Milnyard Square, Orton Southgate, Peterborough PE2 6CX

    </span>

    <div class="clear"></div>

</div> <!-- /wrapper -->

</body>
</html>

上一个和下一个按钮无法正常工作,例如我点击下一步然后我转到第2页,再次点击下一步 - 它的空白,然后点击最后一次我被告知我没有更多的结果可供查看。但是,如果我点击之前的开始并返回3次(再次开始)然后点击下一步我可以循环回到相同的问题,这真的让我感到困惑,任何帮助都将深表感谢!

1 个答案:

答案 0 :(得分:0)

只是阅读你的代码我有一些评论。

此:

$('span.issuecount').html(+totalIssues+'&nbsp;Issues - '+numPages+'&nbsp;Pages');

在'totalIssues'之前应该没有'+',还是我错过了什么?

$('span.issuecount').html(totalIssues+'&nbsp;Issues - '+numPages+'&nbsp;Pages');

结束

$('<li id="'+id+'"></li>').html('<a href="'+url+'"><img src="images/covers/'+cover+'" alt="" /></a><br />'+date+' - #'+issue+'').fadeIn(500).appendTo(shelf);

似乎是在错误的顺序做事,不是吗?先褪色然后追加到?

$('#prevIssueButton').click(function() {
                if( startIndex < howMany) {
                    startIndex -= howMany;
                    displayIssues();

看起来也很奇怪,如果startIndex确实小于howMany,那么此调用后startIndex将为负数,是否有意?

然后我不确定将所有代码都放在Ajax调用的成功事件处理程序中是个好主意。我会把这些东西分开,但也许你已经尝试过并决定了这一点。这只是一个想法。