Question

我正在遍历数组数组。每个元素都有三个值。第三个值可以是High，Med或Low

我想输出

http://maps.google.com/mapfiles/ms/icons/red-dot.png for High
http://maps.google.com/mapfiles/ms/icons/yellow-dot.png for Med
http://maps.google.com/mapfiles/ms/icons/green-dot.png for Low

当价值为High（输出红色）或输出绿色时，我所拥有的效果非常好。

for( i = 0; i < markers.length; i++ ) {
    var position = new google.maps.LatLng(markers[i][0], markers[i][1]);
    bounds.extend(position);
    marker = new google.maps.Marker({
        position: position,
        icon: markers[i][2] === 'High'? 'http://maps.google.com/mapfiles/ms/icons/red-dot.png' : 'http://maps.google.com/mapfiles/ms/icons/green-dot.png',
        map: map,
        title: "",
    });
}

问题

如何如上所述为High, Med, Low工作？

Answer 1

您可以使用对象：

 def __init__(self, name, server, province):
        stats2 = get_info_doll(province, server, name, "2")
        self.attributename = self.Doll2(stats2)

然后使用var icons = { "High": "http://maps.google.com/mapfiles/ms/icons/red-dot.png", "Med": "http://maps.google.com/mapfiles/ms/icons/yellow-dot.png", "Low": "http://maps.google.com/mapfiles/ms/icons/green-dot.png", };或类似的东西。

Answer 2

创建简单的地图对象：

var icons = {
    High: "http://maps.google.com/mapfiles/ms/icons/red-dot.png",
    Med: "http://maps.google.com/mapfiles/ms/icons/yellow-dot.png",
    Low: "http://maps.google.com/mapfiles/ms/icons/green-dot.png"
};

并像这样使用它：

for ( i = 0; i < markers.length; i++ ) {
    var position = new google.maps.LatLng(markers[i][0], markers[i][1]);
    bounds.extend(position);
    marker = new google.maps.Marker({
        position: position,
        icon: icons[markers[i][2]],
        map: map,
        title: "",
    });
}

Answer 3

我知道这不是一个很好的阅读，但如果您想使用仅三元运算符，请将(markers[i][2] === 'Med'? '': '')条件用于markers[i][2] === 'High'?的虚假条件。

icon: markers[i][2] === 'High'? 'http://maps.google.com/mapfiles/ms/icons/red-dot.png' 
: (markers[i][2] === 'Med'? 'http://maps.google.com/mapfiles/ms/icons/yellow-dot.png'
:'http://maps.google.com/mapfiles/ms/icons/green-dot.png')

如何使用三元运算输出三个结果的值

3 个答案: