我正在尝试在PrestaShop中调用Web服务，但我得到401未经授权的错误。即使我已通过用户名密钥。我也试过了验证器，但是我得到了一个错误HttpRetryingError。
在下面找到我所做的代码片段。
方法一：
final String username = "key_here";
final String password = "";// leave it empty
URL urlToRequest = new URL(urlStr);
urlConnection = (HttpURLConnection) urlToRequest.openConnection();
urlConnection.setDoOutput(true);
urlConnection.setRequestMethod("GET");
urlConnection.setRequestProperty("Content-Type",
"text/xml;charset=utf-8");
String authToBytes = username + ":" + password;
//....
byte[] authBytes = org.apache.commons.codec.binary.Base64.encodeBase64(authToBytes.getBytes());
String authBytesString = new String(authBytes);
//then your code
urlConnection.setRequestProperty("Authorization","Basic " + authBytesString);
int statusCode = urlConnection.getResponseCode(); ---> i get 401
if (statusCode != HttpURLConnection.HTTP_OK) {
// throw some exception
InputStream in =
new BufferedInputStream(urlConnection.getInputStream());
Log.e("tag", getResponseText(in));
}
方法二
final String username = "keyvaluehere";
final String password = "";// leave it empty
String authToBytes = username + ":" + password;
byte[] authBytes = org.apache.commons.codec.binary.Base64.encodeBase64(authToBytes.getBytes());
String authBytesString = new String(authBytes);
HttpParams httpParameters = new BasicHttpParams();
// Set the timeout in milliseconds until a connection is established.
// The default value is zero, that means the timeout is not used.
int timeoutConnection = 30000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT)
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 30000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
HttpClient httpclient = new DefaultHttpClient(httpParameters);
HttpGet httpGet = new HttpGet(url);
httpGet.setHeader("Authorization","Basic " +authBytesString);
try {
HttpResponse response = httpclient.execute(httpGet);
String strResponse = EntityUtils.toString(response.getEntity());
if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
return strResponse;
}
return strResponse;
}catch(ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
我甚至尝试将字符串作为ws_key和keyvalue传递，我甚至将网址称为http://keyvalue@domain.com/api/namehere
但它也不起作用。 请协助。
答案 0 :(得分：3)
我知道这是一个老问题，但我想我可以提供帮助。
检查.htaccess文件。它应该有这样的行：
RewriteRule . - [E=REWRITEBASE:/]
RewriteRule .* - [E=HTTP_AUTHORIZATION:%{HTTP:Authorization}]
RewriteRule ^api$ api/ [L]
RewriteRule ^api/(.*)$ %{ENV:REWRITEBASE}webservice/dispatcher.php?url=$1 [QSA,L]
第二行告诉Apache如何处理授权。