Question

我正在维护一款在iPhone 6和iPhone 6 Plus发布之前开发的应用程序。应用程序的开发人员使用代码在屏幕上放置元素。他们根据屏幕高度的点检测屏幕高度。作为应用程序的维护者，我需要确保该应用程序在最新版本的iPhone上运行良好。该应用似乎在iPhone 6和6+上运行良好而无需修改，返回的屏幕高度为568.应用程序在实际设备上表现良好还是模拟器错误？

Answer 1

您可能无法通过App Store获取该应用。问题是该应用不实际上＆＃34;运作良好＆＃34 ;; iPhone 6和iPhone 6 Plus将它视为iPhone 5应用程序并将其显示在＆＃34;缩放＆＃34;模式。 Apple可能不会在新提交的版本中接受它。如果你给项目一个启动屏幕，它将成为一个原生的＆＃34; iPhone 6和iPhone 6 Plus应用程序，然后您将看到故事的真实情况。

Answer 2

马特是对的。我在Utilities类中编写了一个用于确定屏幕大小的方法。注释告诉您每个设备的日志应该返回什么。除了iPhone 6 Plus之外，屏幕尺寸和报告的尺寸都是相同的。

+ (NSInteger)deviceType {
    CGSize screenSize = [[UIScreen mainScreen] bounds].size;
    CGFloat deviceScale = [UIScreen mainScreen].scale;
    LFDeviceType device = LFDeviceTypePhoneClassic;

    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
        device = LFDeviceTypePhoneClassic; // Just in case it doesn't make it through the conditionals
        // Classic has a resolution of 480 × 320
        if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 1.0f ) {
            device = LFDeviceTypePhoneClassic;
        // Retina has a resolution of 960 × 640
        } else if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 2.0f ) {
            device = LFDeviceTypePhoneRetina3_5;
        // Retina 4" has a resolution of 1136 x 640
        } else if (screenSize.height == 568 || screenSize.width == 568 ) {
            device = LFDeviceTypePhoneRetina4;
        // iPhone 6 has a resolution of 1334 by 750
        } else if (screenSize.height == 667 || screenSize.width == 667 ) {
            device = LFDeviceTypePhone6;
        // iPhone 6 Plus has an actual size of 2208 × 1242 and resolution of 1920 by 1080
        // Reported size is 736 x 414 @3x
        } else if (screenSize.height == 736 || screenSize.width == 736 ) {
            device = LFDeviceTypePhone6Plus;
        }

    } else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
        device = LFDeviceTypePadClassic; // Just in case it doesn't make it through the conditionals
        if(deviceScale == 1.0f) {
            device = LFDeviceTypePadClassic;
        } else if (deviceScale == 2.0f) {
            device = LFDeviceTypePadRetina;
        }
    }
    //NSLog(@"The device is %@ scale is %f and the height is %f and width is %f", device, deviceScale, screenSize.height, screenSize.width);

    return device;
}

Answer 3

目前你的应用程序正在以缩放模式工作，如果你添加6和6+的启动画面，那么你的应用程序将是实际大小，在包含6和6+的启动画面后，你将获得实际的屏幕尺寸。

是否检测到iPhone 6和6+高度为568分？

3 个答案: