Question

<?php
include 'preCode.php';
include 'header.php';
echo '<body><div class="standardLayout">';
include 'systemMenu.php';
echo '<h4>All Charges</h4>';

$user = unserialize($_SESSION['user']);  
$query = "SELECT * FROM billingItems WHERE  userID= ' ".$user->userID. " '   ORDER BY deliveryTimestamp DESC"; 
$result = mysqli_query($db, $query);
while($row = mysqli_fetch_array($result))
{
    echo '<p>';

    echo '<a href="billingHistory1.php?deliveryTimestamp=' .$row["deliveryTimestamp"]. '">'.
   ' Order Delivered on' . '</a>' .$row['deliveryTimestamp']  ;
}

echo '</div></body></html>';

$_SESSION['user'] = serialize($user);
include 'footer.html';
?>

上述文件的输出：

  All Charges

  Order Delivered on2015-05-06 13:26:50
  Order Delivered on2015-05-06 13:26:50
  Order Delivered on2015-05-06 13:26:50
  Order Delivered on2015-05-03 22:11:23
  Order Delivered on2015-05-03 22:11:23
  Order Delivered on2015-05-03 22:11:23
  Order Delivered on2015-05-03 22:11:23

如果您将看到输出，那么您会注意到前三个链接相同，后四个相同。

我需要将多个链接减少到一个。

只想为每个链接显示两个链接。

为此，我需要在while循环中使用if语句。如果deliveredTimestamp相同，则不显示它，否则显示它。请帮忙。

Answer 1

为什么不尝试将唯一的deliveryTimestamps添加到数组中，然后从那些链接中呈现链接？

$timestamps = array();
while($row = mysqli_fetch_array($result)){
    if ( !in_array($row['deliveryTimestamp'], $timestamps)) {
        array_push($timestamps, $row['deliveryTimestamp']);
    }
}
foreach ($timestamps as $timestamp) {
    echo '<p>';
    echo '<a href="billingHistory1.php?deliveryTimestamp='.$timestamp.'">'.
         ' Order Delivered on' . '</a>' .$timestamp  ;
    echo '</p>';
}

Answer 2

您可以使用分组依据来减少记录数量

使用此查询

$query = "SELECT * FROM billingItems 
          WHERE  userID= ' ".$user->userID. " ' 
          GROUP BY deliveryTimestamp 
          ORDER BY deliveryTimestamp DESC";

如何显示一个链接而不是多个链接？

2 个答案: