Question

我正在尝试获取基本的JSONP查询：

<html>
    <head>
        <script type="text/javascript" src="js/jquery1.js"></script>
        <script>
            $(document).ready(function(){
                $.ajax({
                    url: 'http://www.bing.com/',
                    dataType: 'jsonp',
                    success: function(dataWeGotViaJsonp){
                        var text = '';
                        var len = dataWeGotViaJsonp.length;

                        $('#text').html(len);
                    }
                });
            })
        </script>
    </head>
    <body>
        <div id = 'text'></div>
    </body>
</html>

我正在使用IE8和jquery v1.11.3

  Syntax error  ?callback=jQuery111309915726215071462_1436849961686&_=1436849961687, line 1 character 1

这是什么回调？它来自哪里？

如果我将网址更改为“https://www.bing.com/search?q=hello+world”

我明白了：

  Syntax error  search?q=hello+world&callback=jQuery11130544191867791898_1436850255384&_=1436850255385, line 1 character 1

Answer 1

    <html>
        <head>
            <script type="text/javascript" src="js/jquery1.js"></script>
            <script>
                $(document).ready(function(event){
               if (event.preventDefault) {
            event.preventDefault();
        }
        else {
            event.returnValue = false;
        }
                    $.ajax({
                        url: 'http://www.bing.com/',
                        dataType: 'jsonp',
                        success: function(dataWeGotViaJsonp){
                            var text = '';
                            var len = dataWeGotViaJsonp.length;

                            $('#text').html(len);
                        }
                    });
                })
            </script>
        </head>
        <body>
            <div id = 'text'></div>
        </body>
    </html>

//使用event.preventDefault。

Answer 2

将dataType: 'jsonp'更改为dataType: 'text'

语法错误？callback = jQuery1113

2 个答案: