hibernate.jpa.HibernatePersistenceProvider无法强制转换为javax.persistence.spi.PersistenceProvider

时间:2015-07-13 23:23:44

标签: hibernate tomcat vaadin jpacontainer

我正在使用vaadin为运行hibernate 4.3.1的应用程序开发UI 我想要做的是将数据绑定到vaadin JPAcontainer,然后在Grid组件中使用它来允许延迟加载。但是当我尝试创建EntityManager时,它会抛出以下错误

java.lang.ClassCastException: org.hibernate.ejb.HibernatePersistence cannot be cast to javax.persistence.spi.PersistenceProvider
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:54)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:39)
at com.vaadin.addon.jpacontainer.JPAContainerFactory.createEntityManagerForPersistenceUnit(JPAContainerFactory.java:122)
at com.vaadin.addon.jpacontainer.JPAContainerFactory.make(JPAContainerFactory.java:105)

我使用了 hibernate-jpa-2.1-api-1.0.0.Final.jar 以及 persistence-api-1.0.2.jar 来导入我的EnityManager但我一直收到同样的错误

这是我创建EntityManager的类

 public class workManager{
    public static void create() {
    DataAccess dao= new DataAccess();

    EntityManager em = Persistence  //error here
            .createEntityManagerFactory("myUI")
            .createEntityManager();

    em.getTransaction().begin();
    dao.init();
    List<work> list = dao.findAll(); //get all rows in table
    em.persist(list);
    dao.close();
    em.getTransaction().commit();
}

的persistence.xml

 <?xml version="1.0" encoding="UTF-8"?>
 <persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
 <persistence-unit name="myProject">
    <!-- Specify the JPA provider to use -->
    <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>

    <!-- Entity beans go here -->
    <class>com.dao.model.Work</class>


    <properties>
        <!-- DB connection properties -->
        <property name="javax.persistence.jdbc.url" value="jdbc:sqlserver://S12345:1111;databaseName=dbName" />
        <!-- property name="javax.persistence.jdbc.url" value="jdbc:sqlserver://L71111:1111;databaseName=dbName" / -->
        <property name="javax.persistence.jdbc.user" value="iaSys" />
        <property name="javax.persistence.jdbc.password" value="password" />
        <property name="javax.persistence.jdbc.driver" value="com.microsoft.sqlserver.jdbc.SQLServerDriver" />

        <!-- Settings for c3p0 connection pooling -->
        <property name="hibernate.connection.provider_class" value="org.hibernate.connection.C3P0ConnectionProvider" />
        <property name="hibernate.c3p0.max_size" value="100" />
        <property name="hibernate.c3p0.min_size" value="0" />
        <property name="hibernate.c3p0.acquire_increment" value="1" />
        <property name="hibernate.c3p0.idle_test_period" value="300" />
        <property name="hibernate.c3p0.max_statements" value="0" />
        <property name="hibernate.c3p0.timeout" value="100" />
    </properties>
</persistence-unit>

在另一个类中我创建了JPAContainer

 private JPAContainer<work> container = JPAContainerFactory.make(work.class,
            JpaProjectUI.PERSISTENCE_UNIT);
 grid.setContainerDataSource(container);

这里是我的EntityManager被称为

的地方
public class JpaPojectUI extends UI {
private static final long serialVersionUID = 1L;
public static final String PERSISTENCE_UNIT = "myProject";

static {
    workManager.create();
}

@Override
protected void init(VaadinRequest request) {
    setContent(new mainUI());
}

我正在关注JPAContainer附加组件附带的AddressBook demo

我使用Tomcat 8来运行我的应用程序

有没有人知道为什么会这样?如果问题不清楚,请随时向我询问更多信息!

以下是我的WEB-INF文件夹中的jar文件

enter image description here

我还在构建路径中添加了另一个项目,其中包含以下jar列表

enter image description here

感谢

1 个答案:

答案 0 :(得分:5)

请从您的网络应用程序中删除persistence-api-1.0.2.jar并查看结果。 hibernate-jpa和persistance-api

之间存在冲突