从Rectangle中删除Path2D

Question

我试图从矩形中删除贝塞尔曲线。我有两种形状，但从Rectangle中减去Path2D对象时遇到一个小问题。这是它的样子：

正如您所看到的，我不希望曲线底部的线条。我的代码是这样的（无需担心值）：

        Path2D path1 = new Path2D.Double();
        path1.moveTo(start_x, start_y);
        path1.curveTo(control1_x, control1_y, control2_x, control2_y, end_x, end_y);
        path1.append(new Line2D.Double(start_x, start_y, end_x, start_y), false);
        path1.closePath();
        g2.setColor(Color.BLUE);

        Area shape = calculateOutside(path1);

        g2.fill(shape);

此外，calculateOutside方法：

    private Area calculateOutside(Path2D path) {
        Area outside = new Area(new Rectangle2D.Double(0, 0, width, height);
        outside.subtract(new Area(path2D));
        return outside;
    }

我还尝试在该曲线下附加一行true作为构造函数值。或尝试没有追加线。我错过了什么？

感谢您的帮助。

此外，如果有人需要，值：

        int start_x = 60, start_y = 76;
        int control1_x = 57, control1_y = 49;
        int control2_x = 83, control2_y = 47;
        int end_x = 80, end_y = 76;