Question

我想使用Selenium webdriver迭代Python中的以下元素。

<ul class="skills-section">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Ear Surgery">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Healthcare">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Hospitals">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Surgery">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Medical Education">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Pediatrics">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Treatment">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Public Health">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Patient Safety">
  <li class="endorse-item has-endorsements " data-endorsed-item-name="Emergency Medicine">
</ul>

我尝试了什么？

skillsSection = a.find_element_by_xpath("//ul[contains(@class, 'skills-section')]")
skillsList = skillsSection.find_elements_by_tag_name("li")
for skill in skillsList:
    print skill.find_element_by_xpath("//span[contains(@class,endorse-item-name')]/a").text

但问题是，它总是打印第一个元素值。元素没有递增。

Answer 1

您要做的是找到带有'ul'的标记class='skills-section'，然后对子项进行迭代。

skillsSection = a.find_element_by_xpath("//ul[contains(@class, 'skills-section')]")
for child in skillsSection.find_elements_by_xpath(".//*"):
    ...

有关详细信息，请参阅此答案：Selenium Python get all children elements

Answer 2

我最近一直处理类似的问题，我只能打印列表中的第一项。我发现了一个需要多行的解决方案，并避免使用xpath。对于您的代码，您可能需要替换：

print skill.find_element_by_xpath("//span[contains(@class,'endorse-item-name')]/a").text

有类似的东西：

a1 = skill.find_element_by_class_name('endorse-item-name')
a2 = a1.find_element_by_tag_name('a')
print a2.text

不像xpath那样优雅，但它（应该）有用。

如何在Python Selenium中迭代无序列表

2 个答案: